Given that we assume that all the bases of the triangles are parallel.
We can use AAA or Angle-Angle-Angle to prove that these triangles are similar.
Each parallel line creates the same angle when intersecting with the same side.
For example:
The bases of each triangle cross the left side of all the triangle.
Each angle made by the intersecting of the the parallel base and the side are the same.
Thus, each corresponding angle of all the triangles are congruent.
If these angles are congruent, then we have similar triangles.
Answer:
no it is not now I am just putting random words
Answer:
Step-by-step explanation:
band alone 11
choir alone 17
band and choir alone 4
band and math alone 7
math and choir alone 6
band choir and math 3
math alone 9 from 11+4+10+6+17 + M = 57
so
2 classes = 4+7+6 = 17
17 students take exactly two classes with Mr. Green
a) Corresponding angles of similar figures are congruent, so 
b) Scale factor = (image)/(preimage). Since we are looking for ABCD to WZYX, this means that WZYX is the image and ABCD is the preimage. Thus, the scale factor is 
c) Since the scale factor is 5/2,
