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adoni [48]
2 years ago
6

Let f(x) =

E%7B%20-%201%7D%20%28x%29" id="TexFormula1" title=" \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)" alt=" \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)" align="absmiddle" class="latex-formula">? here ​
Mathematics
1 answer:
crimeas [40]2 years ago
3 0

Step-by-step explanation:

Set up f(x).

\sqrt[3]{11x - 3}  = f(x)

Replace f(x) with y

\sqrt[3]{11x - 3}  = y

Swap x and y

\sqrt[3]{11y - 3}  = x

Solve for y

Cube both sides

11y - 3 =  {x}^{3}

Add 3 to both sides

11y =  {x}^{3}  + 3

Divide both sides by 11

y =  \frac{x {}^{3} + 3 }{11}

so

f {}^{ - 1} (x )=  \frac{ {x}^{3}  + 3}{11}

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Step-by-step explanation:

4^5 (-2)^9/4^8 (-2)^3

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1). (-2)^a/4^b

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2). c/d

c = -2, d = 4

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3 years ago
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Answer:

Step-by-step explanation:

1. Height of the equilateral triangle = a√3/2

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Find the common difference of the sequence shown. 1/6, 1/3, 1/2 , 2
Morgarella [4.7K]

Answer:

1/6

Step-by-step explanation:

sequence should be 1/6,1/3,1/2,2/3

common difference=1/3-1/6=2/6-1/6=1/6

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3 years ago
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Read 2 more answers
Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

7 0
2 years ago
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