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adoni [48]
3 years ago
6

Let f(x) =

E%7B%20-%201%7D%20%28x%29" id="TexFormula1" title=" \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)" alt=" \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)" align="absmiddle" class="latex-formula">? here ​
Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Step-by-step explanation:

Set up f(x).

\sqrt[3]{11x - 3}  = f(x)

Replace f(x) with y

\sqrt[3]{11x - 3}  = y

Swap x and y

\sqrt[3]{11y - 3}  = x

Solve for y

Cube both sides

11y - 3 =  {x}^{3}

Add 3 to both sides

11y =  {x}^{3}  + 3

Divide both sides by 11

y =  \frac{x {}^{3} + 3 }{11}

so

f {}^{ - 1} (x )=  \frac{ {x}^{3}  + 3}{11}

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