Well, the area of a trapezoid is A = (
+ 
) * h * 1/2 so you can use the area of a parallelogram, which is A = l * w, by splitting the trapezoid into 2 triangles and one rectangle. So you'd use A = l * w for the rectangle and A = 1/2bh for the triangles. You'd get the same answer!
Which is the graph of f(x)=2(3)^x
1 answer:
<u>Answer-</u>
<em>The </em><em>first graph</em><em> represents </em>
<u>Solution-</u>
The given function is,
Putting x = 1,
So, the point (x, f(x)) i.e (1, 6) must satisfy or lie on the curve of the function.
Only in case of the first graph, the point (1, 6) lies on the curve.
Therefore, the first graph represents the function correctly.
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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band