I am assuming you meant to write the following options
A. f(x)=x+3; g(x)=√x
B. f(x)=x; g(x)=x+3
C. f(x)=√x; g(x)=x+3
D. f(x)=3x; g(x)=√x
You need to find a fucntion f(x) that once evaluated in g(x) gives us as a result h(x)
h(x) = g(f(x))
Looking at the options, the answer is A.
g(f(x)) = sqrt(f(x)) = sqrt (x + 3) = h(x)
Answer:
9/4
Step-by-step explanation:
2(x - 10) + 4 = -6x + 2
2x - 20 + 4 = -6x + 2
2x - 16 = -6x + 2
8x - 16 = 2
8x = 18
x = 18/8 or 9/4
x=50
Step-by-step explanation:
angle 1 and 3 are corresponding angles that menas they equal the same
so set it up like this 2x+10=110 solve for x
move over the 10, subtract 10 from 110 you get 100 and divide by 2
you get 50.
<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
