Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
y =5x
Step-by-step explanation:

(5 - 0) = m(1 - 0)
5 = m(1)
5 = m

y - 5 = 5(x - 1)
y - 5 = 5x - 5
y = 5x -5 + 5
y = 5x
Answer:
y=1x+-1
Step-by-step explanation:
y=mx+b
m=slope which is 1/1 because it is rise over run (rising 1, running 1)
b=y-intercept form which is -1 because that is where the line meets the y axis
You can't solvd monomials because they are just 1 term multiplication :
example: 2a , or 14