The function H(t) = −16t2 + 90t + 50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
he air along a path represented by g(t) = 28 + 48.8t, where g(t) is the height, in feet, of the object from the ground at time t seconds. Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points)
Part B: Explain what the solution from Part A means in the context of the problem. (4 points)
The solution is between 3 and 4 seconds because it can be seen that there was a shift in the trend between them. H(t) had higher values for the first 3 seconds. It can be seen that in 3 seconds, g(t) is already approaching H(t). Finally, at 4 seconds, g(t) surpasses H(t).
For the answer to part B This means that between 3 and 4 seconds, g(t) was able to catch up to H(t) in terms of height. At H(t)=g(t), this gives 3.03 secs which is indeed between 3 and 4 seconds. Above 3.03 seconds, g(t) overtakes the height of H(t).
If x is fish, y is octopi, and z is crabs, then you would have to know the numbers. Then your answer would be c. 30x+80y-15z. Because x=+30, y=+80, and z=-15. I hope that helps. If you need any further help on this problem just ask.
1.The height is 6 inches ad the width (diameter) is 3 inches! 2. So the jars are Volume ≈ 42.41 inches so each boy needs 200 / 42.41 which equals approximately 4.72 inches per jar. So if wach boys have half the amount of jars which is 20 you multiply 20 by 4.72 which is 94.4 inches for each boy!
47x > = 209....with x being number of lawns mowed x > = 209 / 47 x > = 4.45....so he would have to mow at least 4.45 lawns.....but if u cant mow part of the lawn and u have to mow the entire lawn, the it would be at least 5 full lawns