Solve the equation. (find x)

Mathematics

1 answer:

Irina-Kira [14]3 years ago

8 0

Answer:

Step-by-step explanation:

$(x^2-3x+1)^{(2x^2+x-6)}=1\ we \ take \ the \ logarithm\\\\(2x^2+x-6)*ln(x^2-3x+1)=0\\\\(2x^2+x-6)=0\ or\ x^2-3x+1=1\\\\1)\\2x^2+x-6=0\\2x^2+4x-3x-6=0\\2x(x+2)-3(x+2)=0\\(x+2)(2x-3)\\x=-2\ or\ x=\dfrac{3}{2} \\\\2)\\x^2-3x=0\\x(x-3)=0\\x=0\ or\ x=3\\\\sol=\{-2,0,\dfrac{3}{2},3\}\\$

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Please also check the attached graph.

Step-by-step explanation:

Given

Given the function

$y=-720t\:+\:3600$

To determine

What is the domain of the function y=-720t + 3600

We know that the domain of the function is the set of input argument values for which the function is real and defined.

Given the function

$y=-720t\:+\:3600$

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Please also check the attached graph.

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steposvetlana [31]

Answer:

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Step-by-step explanation:

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