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Vinvika [58]
3 years ago
5

Complete the table for the given rule.

Mathematics
1 answer:
katovenus [111]3 years ago
7 0

xxxyyy111 is the answer

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A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
Christopher is 20 years younger than Ishaan. Ishaan and Christopher first met two years ago. Fourteen years ago, Ishaan was 3 ti
VLD [36.1K]

Answer:

44

Step-by-step explanation:

7 0
3 years ago
Evaluate the expression a +7 when a=4, b=2, and c=8
tatyana61 [14]

Answer:

a + 7

so "a" is 4 so

4+7=11

Hope this helps!

8 0
3 years ago
Read 2 more answers
What is 1/3 divided by 5/6?<br> Please help me don’t get it
hammer [34]

Answer:

=0.4

Step-by-step explanation:

1/3= 0.33

5/6=0.83

Then: 0.33/0.83 = 0.4

You can also do 6/15 which results from (1*6)=6 and (3*5)=15

3 0
3 years ago
Read 2 more answers
If k = p+2q/3 , find the value of p when k=7 and q=3​
marishachu [46]

Answer:

p = 5

Step-by-step explanation:

hopefully it is clear and understandable :)

6 0
3 years ago
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