Answer:
Here we have the domain:
D = 0 < x < 1
And we want to find the range in that domain for:
1) y = f(x) = x
First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)
f(0) = 0 is the minimum in the range.
f(1) = 1 is the maximum in the range.
The range is:
0 < y < 1.
2) y = f(x) = 1/x.
In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.
f(0) = 1/0 ---> ∞
f(1) = 1/1
Then the range is:
1 < x.
Notice that we do not have an upper bound.
3) y = f(x) = x^2
This function is strictly increasing, then:
f(0) = 0^2 = 0
f(1) = 1^2 = 1
the range is:
0 < y < 1
4) y = f(x) = x^3
This function is strictly increasing in the interval, then:
f(0) = 0^3 = 0
f(1) = 1^3 = 1
the range is:
0 < y < 1.
5) y = f(x) = √x
This function is well defined in the positive reals, and is strictly increasing in our domain, then:
f(0) = √0 = 0
f(1) = √1 =1
The range is:
0 < y < 1
-6m+19
1/2(-12m+38)
All we have to do is simply distribute the 1/2.
1/2(-12m) + 1/2(38)
(-6m) + 19
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Answer:
Major Arc should be your answer
Trust
The expression that can complete the blank is 6y^3
<h3>What are expressions?</h3>
Expressions are mathematical statements that are represented by variables, coefficients and operators
<h3>How to complete the blanks?</h3>
The expression is given as
2/y^2=_/3y^5
Replace the blank with x
So, we have
2/y^2 = x/3y^5
Multiply both sides of the equation by 3y^5
So, we have
x = 3y^5 * 2/y^2
Evaluate the products
x = 6y^3
This means that the blank is 6y^3
Read more about expressions at
brainly.com/question/723406
#SPJ1
We know that
for a Square Pyramid
[lateral area]=4*[a*s/2]--------> 2aS
where
a is the length side of the square base
S is the slant height
a=145 ft
S=856.1 ft
[lateral area]=2*145*856.1---------> 248269 ft²
the answer is 248269 ft²
