The dimensions of the rectangular base will be 110ft by 330ft the length of the base measures less than 3 times the width
The formula for calculating the perimeter of the rectangular base is expressed as:
P = 2(L +W) where;
L is the length
W is the width
If the length of the base measures less than 3 times the width, then L < 3W
Given that Perimeter = 880feet
Substitute the given value into the formula to get the length
880 = 2(3W+W)
880 = 2(4W)
880 = 8W
W = 880/8
W = 110ft
Since L = 3W
L = 3(110)
L = 330ft
Hence the dimensions of the base will be 110ft by 330ft
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Answer:
If its written like as a fraction like s+20/6 then s=22
Step-by-step explanation:
Answer:
Domain: (-∞, ∞) or All Real Numbers
Range: (0, ∞)
Asymptote: y = 0
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Step-by-step explanation:
The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.
The range is from 0 to ∞. This where all values of y are defined.
An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.
The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Answer:
$440,000
Step-by-step explanation:
Sales : $1,800,000
Gross profit : (30% × 1,800,000) : $540,000
Cost of goods sold (Sales-profit) : $1260,000
Beginning inventory : $500,000
Purchasing : $1,200,000
Total : $1,700,000
Goods sold (subtract) : $1,260,000
Closing inventory : $440,000
Answer:
The invalid statement is 4) Segment AP is congruent to segment PQ.
We conclude that 2) Segment RB is congruent to segment CS.
Step-by-step explanation:
Given, line segment AB & CD
Here, P is the midpoint of AB ⇒ AP=PB
& Q is the midpoint of CD ⇒ CQ=QD
It is given that P is point on AB not on CD ∴ there is no relation of point P with line segment CQ.
Hence, the invalid statement is
Segment AP is congruent to segment PQ.
Now, given that R is the midpoint of AP ⇒ AR=RP
& S is the midpoint of QD ⇒ QS=SD
AB≅CD (Given)
≅
PB ≅ CQ (∵from midpoint statements)
∵ PA=QD ⇒ PR=QS
Because PB≅CQ
PB+PR≅CQ+QS
⇒ RB≅CS
Therefore, Segment RB is congruent to segment CS