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lara31 [8.8K]
2 years ago
7

What are the zeros of the function f(x) = x2 + 7x – 18? Enter your answers in the boxes with your greatest answer first. The zer

os of f(x) ar AN A/​
Mathematics
1 answer:
Andru [333]2 years ago
7 0

Answer:

The answer is 2 and (-9)

Step-by-step explanation:

x² + 7x – 18 = 0

x² + 9x – 2x – 18 = 0

x(x + 9) – 2(x + 9) = 0

(x – 2) (x + 9) = 0

x = (2, -9)

Thus, The zeroes of the polynomial is 2 and (-9).

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Answer:

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8 0
3 years ago
Please help! A-level maths.
astra-53 [7]

x+y=k\implies y=k-x

Substitute this into the parabolic equation,

k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0

We're told the line x+y=k intersects C twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5

and

-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6

so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

4 0
3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
Evaluate 2^3 [(15-7)] (4 divided by 2)].
Vanyuwa [196]

2^3= 8

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8 * 8 * 2

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answer: 128

5 0
4 years ago
Simplify cos^4x+2cos^2xsin^2x+sin^4x
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Answer: 1

Step-by-step explanation:

5 0
3 years ago
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