Ask question

Ask question

All categories

3 years ago

6

On the graph of the equation X-4Y= -16 what is the value of the Y-intercept?

1 answer:

Nonamiya [84]3 years ago

8 0

we can always find the x-intercept by simply settting y = 0, and solving for "x".

and we can always find the y-intercept by simply setting x = 0 and solving for "y".

$\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill (0,4)~\hfill$

You might be interested in

Find the area of the figure.<br> help asap!

Alborosie

165

5x5= 25
12x12=144
25+144= 165

4 0

3 years ago

Read 2 more answers

Explain how to find the surface area of a 3-D figure

german

Well, for any prism, it is the lateral area + the area of two ends.

8 0

3 years ago

Solve this equation <br>(3m⁴)²

earnstyle [38]

Answer:

9m⁸

Step-by-step explanation:

3^2=9

(m⁴)² = m⁸

9*m⁸

4 0

3 years ago

ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R

shutvik [7]

Answer:

$A'= (2,-1)$ and $R'=(4,-2)$ under this translation.

Step-by-step explanation:

A translation in $R^{2}$ is a mapping T from $R^{2}$ to $R^{2}$ defined by $T(x,y) = (x + v_1,y+v_2)$ , where $v=(v_1,v_2)$ is a fixed vector in $R^{2}$ .

From the problem we know that $T(2,4)=(3,2)$ , so we need to find the values $v_1$ and $v_2$ such that $T(2,4) = (2 + v_1,4+v_2)=(3,2)$ , so $3=2 + v_1$ and $4+v_2=2$ , thus $v_1=1$ and $v_2=2$ .

Then $T(x,y) = (x + 1,y-2)$ and

$T(1,1)=(1+1,1-2)=(2,-1)=A'$

$T(3,0)=(3+1,0-2)=(4,-2)=R'$

Therefore $A'= (2,-1)$ and $R'=(4,-2)$ . The triangles CAR and C'Q'R' are shown in the figure below.

7 0

3 years ago

Please show all your work!!!

Alex73 [517]

Answer:

y= -6/5x -3

Step-by-step explanation:

So for now lets bring it into mx + b format

Subtract 6x from both sides to isolate y which is also called subtraction property of equality.

so 5y = -6x -15

Now you divide both sides by 5 which is called division property of equality.

You now have y = -6/5x - 3

y= -6/5x -3 is the slope intercept form of the standard form equation of 6x + 5y = -15.

Hope this helps!

3 0

3 years ago