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Varvara68 [4.7K]
2 years ago
5

Please help with this math problem

Mathematics
1 answer:
zimovet [89]2 years ago
3 0

x=2+½*\sqrt{10}

or

x=2-½*\sqrt{10}

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

2x²-5x-3x+6-3=0

2x²-8x+3=0

comparing above equation with ax²+bx+c=0 we get

a=2

b=-8

c=3

by using quadratic equation

x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}

x=\frac{+8±2\sqrt{10}}{4}

taking positive

x=\frac{+8+2\sqrt{10}}{4}

x=2+½*\sqrt{10}

taking negative

x=2-½*\sqrt{10}

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