Find the solutions of the quadratic equation 7?

Leona [35]

Thus, we need information about the sides OQ and PQ to solve the triangle and find the area. The information given is not enough to determine the area of the triangle.

<h3>Is this triangle solvable?</h3>

In this question we must analyze if the area of the triangle OPQ can be found by all information given. By the law of the cosines we understand that lengths of two sides and the measure of an angle should be known to construct a triangle and by the law of the sines we understand that either two angles and a side or two sides and an angle must be known.

Thus, we need information about the sides OQ and PQ to solve the triangle and find the area. The information given is not enough to determine the area of the triangle.

To learn more on triangles: brainly.com/question/25813512

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5 0

2 years ago

Need help with this math problem

Shkiper50 [21]

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Step-by-step explanation:

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Taking a bottom-left corner of the graph as (0,0)

Given Line AB,

Point A is located as (4,9)

Point B is located as (16,1)

The slope of AB is

$=\frac{Y1-Y2}{X1-X2}$

$=\frac{9-1}{4-16}$

$=\frac{8}{-12}$

$=\frac{-2}{3}$

The question says " Draw a line passes through C(13,12) and parallel to Line AB "

Now, Let the equation of the target line is y=mx + c

Where m=slope and c is the y-intercept

The target line is parallel to the line AB

The slope of the Target line = The slope of the Line AB $=\frac{-2}{3}$

m= $=\frac{-2}{3}$

We can write, the equation of the target line is

$y=\frac{-2}{3}x + c$

Also, the Target line is passing through C(13,12)

Point C satisfies the equation

$y=\frac{-2}{3}x + c$

$12=\frac{-2}{3}13 + c$

$12=\frac{-26}{3} + c$

$12+\frac{26}{3}=c$

$c= 12+\frac{26}{3}$

$c= \frac{62}{3}$

Replacing the value

the equation of the target line is

$y=\frac{-2}{3}x + c$

$y=\frac{-2}{3}x + \frac{62}{3}$

$3y= -2x + 62$

It is also asked that if a line is extended , would it passes through the (18,-8)?

If a line passes through the point (18-,8) then, that point must satisfy the equation of a line

the equation of the target line is $3y= -2x + 62$

$3(-8)= -2(18) + 62$

$(-24)= (-36) + 62$

$(-24)= 26$

Left land side is not equal to right hand side.

Therefore. a line does not pass through the point (18,-8)

5 0

3 years ago

Solve for W<br> -3W +27 = 6

vfiekz [6]

Answer:

the answer will be 7 w = 7

Step-by-step explanation:

5 0

3 years ago

Find EM.<br> Can anyone help me with this?

Komok [63]

The little red dashes on the segments means they are congruent. EM = MG

Let's plug the expressions from the picture into our equation above.

7x = 8x - 6

Subtract 8x from both sides.

-x = -6

Divide both sides by -1

x = 6

EM = 7x = 7(6) = 42

6 0

3 years ago

mr. dean has an even number of cats and an odd number of dogs. which of these choices could tell about his pets ? 6 cats and 3 d

valina [46]

Even numbers can be divided evenly into groups of two. The number four can be divided into two groups of two.

Odd numbers can NOT be divided evenly into groups of two. The number five can be divided into two groups of two and one group of one.

Even numbers always end with a digit of 0, 2, 4, 6 or 8.
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 are even numbers.

Odd numbers always end with a digit of 1, 3, 5, 7, or 9.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 are odd numbers.

The correct answer is 6 cats and 3 dogs.

4 0

3 years ago

Find the solutions of the quadratic equation 7? - 2c +3 = 0.