Answer: 21%
Step-by-step explanation:
Percent by definition is based on "out of 100." If 21 out of 100 has high cholesterol, then the percentage is 21%
The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²
<h3>
Circle Equation</h3>
The standard equation of a circle is given by:
(x - h)² + (y - k)² = r²
Where (h, k) is the center of the circle and r is the radius.
Given that diameter = 15 miles, hence radius = 15/2 = 7.5. Also, center = (80, 26)
The equation of circle is:
(x - 80)² + (y - 26)² = 7.5²
The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²
Find out more on Circle Equation at: brainly.com/question/1559324
This = one 1/2 circle with radius 2 in and one with radius 1
= 2pi + pi = 3pi = 9.42 in to nearest hundredth
No, it is not a solution, as 15 is not less-than fifteen.<span />
Answer:
Part a) The height that the liquid forms equals 2.56 feet.
Part b) The number of trucks required are 361.
Step-by-step explanation:
When all the liquid mixture is spilled from the storage tank it will accumulate over the floor space.
Thus we infer
![V_{spilled}=V_{accumulated}](https://tex.z-dn.net/?f=V_%7Bspilled%7D%3DV_%7Baccumulated%7D)
where
is spilled volume of mixture = ![2900m^{3}](https://tex.z-dn.net/?f=2900m%5E%7B3%7D)
is accumulated volume over the floor
Since the floor is smooth thus we conclude that the accumulated volume will form a prism of liquid with height 'h'
Thus
![V_{accumulated}=Area\times h=40000\times h](https://tex.z-dn.net/?f=V_%7Baccumulated%7D%3DArea%5Ctimes%20h%3D40000%5Ctimes%20h)
Equating both the volumes we get
![40000\times h=2900m^{3}\times \frac{35.314ft^{3}}{m^{3}}=102412.533ft^{3}\\\\\therefore h=\frac{102412.533}{40000}=2.56 feet](https://tex.z-dn.net/?f=40000%5Ctimes%20h%3D2900m%5E%7B3%7D%5Ctimes%20%5Cfrac%7B35.314ft%5E%7B3%7D%7D%7Bm%5E%7B3%7D%7D%3D102412.533ft%5E%7B3%7D%5C%5C%5C%5C%5Ctherefore%20h%3D%5Cfrac%7B102412.533%7D%7B40000%7D%3D2.56%20feet)
Thus the height formed by the liquid equals 2.56 feet.
Part b)
We know that the basic relation between density, mass and volume is
![Mass=density\times volume](https://tex.z-dn.net/?f=Mass%3Ddensity%5Ctimes%20volume)
Since it is given that the density of the liquid is 112% the density of water thus we have
![density_{liquid}=1.12\times density_{water}\\\\density_{liquid}=1.12\times 1000=1120kg/m^3](https://tex.z-dn.net/?f=density_%7Bliquid%7D%3D1.12%5Ctimes%20density_%7Bwater%7D%5C%5C%5C%5Cdensity_%7Bliquid%7D%3D1.12%5Ctimes%201000%3D1120kg%2Fm%5E3)
Thus the weight of the volume of liquid is
![mass=2900\times 1120=3248000kg](https://tex.z-dn.net/?f=mass%3D2900%5Ctimes%201120%3D3248000kg)
Now since it is given that 1 truck can carry 9000 kg of liquid thus by proportion the number of trucks need to carry 3248000 kilograms of liquid equals