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Thepotemich [5.8K]

3 years ago

8

Help anyone know this???

1 answer:

s2008m [1.1K]3 years ago

7 0

The first one is right

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Hhiycycucucicuvuvuvu

suter [353]

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2 years ago

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Write 0.00605 in scientific notation.

vichka [17]

How many jumps is it from the decimal point to the position to the right of the 6

The answer to that is 3 jumps. Since the move of the decimal made the number larger than it really is, it will take a negative value to put it back where it belongs.

So A) is the correct answer. It is in scientific notation and if you move the decimal back 3 place you get the number you stared with.

5 0

3 years ago

What is the perimeter of a rectangle that has a length of 40 Ft and a width of 17 ft?

statuscvo [17]

Answer:

i think 114ft

Step-by-step explanation:

5 0

1 year ago

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What is the equation of the line that goes through the points (4,-1) and<br> (2,3)?

Arturiano [62]

Answer:

<u>y = -2x + 7</u>

Explanation:

<em><u>y = mx + b</u></em>

<em><u /></em>

<em>m = slope</em>

<em>b = y-intercept</em>

<em>y = a given y coordinate</em>

<em>x = a corresponding x coordinate</em>

<em />

First, we need to find the slope (m).

1) (4, -1)

2) (2/3)

m = slope = $\frac{y_2-y_1}{x_2-x_1}$ = $\frac{3-(-1)}{2-4}$ = $\frac{4}{-2}$ = -2

plug in the values to the equation <u>y = mx + b</u>

<u />

-1 = -2(4) + b

-1 = -8 + b

7 = b

now, we can substitute in m and b into the equation y = mx + b

<u><em>y = -2x + 7</em></u>

5 0

2 years ago

Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago