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Elenna [48]
3 years ago
12

Which is the mode for the data set? −1, 0, 3, 4, −3, −1 0.3 −1 2 −0.5

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

Mode is the number that appears most often

−1, 0, 3, 4, −3, −1

-1 appears twice which is more than any other number

-1 is the mode

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An SRS of ten brands of breakfast cereals is tested for the number of calories per serving. The following data result: 185, 190,
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Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

From the sample and the significance level of 0.05, we have that the parameters are given by:

\overline{x} = 205.5, s = 14.2, n = 10, t = 2.2622

Hence:

\overline{x} - t\frac{s}{\sqrt{n}} = 205.5 - 2.2622\frac{14.2}{\sqrt{10}} = 195.3

\overline{x} + t\frac{s}{\sqrt{n}} = 205.5 + 2.2622\frac{14.2}{\sqrt{10}} = 215.7

The 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

More can be learned about the t-distribution at brainly.com/question/16162795

8 0
2 years ago
3t^8 in standard form
Sunny_sXe [5.5K]

Answer:

that is in standard form?? are u talking about monomials?

Step-by-step explanation:

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2 years ago
you get 90 pills from the pharmacy every 28 days . you take 3 per day., but you lost 8 pills. how many pills per day are you lef
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If you have 90 pills from the pharmacy every 28 days, and you take 3 per day, but lost 8. You will end up with 82 when you lost the 8 pills. Does it tell you how many days you took the pills for or is it just asking what you have left after losing 8 of them?
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Assume that there is a 8​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
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Answer:

0.9936 = 99.36% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk, there are only two possible outcomes. Either it works, or it does not. The probability of a disk working is independent of any other disk, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that there is a 8​% rate of disk drive failure in a year.

So 100 - 8 = 92% probability of working, which means that p = 0.92

Two disks are used:

This means that n = 2

What is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.92)^{0}.(0.08)^{2} = 0.0064

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0064 = 0.9936

0.9936 = 99.36% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

8 0
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The answer is A because you would do 79 x 0.05 which equals 3.95 . So you subtract 3.95 from 79 which is 75.05 minus 50 equal to 25.05
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3 years ago
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