The knob at the front of the miter saw about belt height is used to adjust the miter angle true or false
1 answer:
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Answer & Explanation:
function Temprature
NYC=[33 33 18 29 40 55 19 22 32 37 58 54 51 52 45 41 45 39 36 45 33 18 19 19 28 34 44 21 23 30 39];
DEN=[39 48 61 39 14 37 43 38 46 39 55 46 46 39 54 45 52 52 62 45 62 40 25 57 60 57 20 32 50 48 28];
%AVERAGE CALCULATION AND ROUND TO NEAREST INT
avgNYC=round(mean(NYC));
avgDEN=round(mean(DEN));
fprintf('\nThe average temperature for the month of January in New York city is %g (F)',avgNYC);
fprintf('\nThe average temperature for the month of January in Denvar is %g (F)',avgDEN);
%part B
count=1;
NNYC=0;
NDEN=0;
while count<=length(NYC)
if NYC(count)>avgNYC
NNYC=NNYC+1;
end
if DEN(count)>avgDEN
NDEN=NDEN+1;
end
count=count+1;
end
fprintf('\nDuring %g days, the temprature in New York city was above the average',NNYC);
fprintf('\nDuring %g days, the temprature in Denvar was above the average',NDEN);
%part C
count=1;
highDen=0;
while count<=length(NYC)
if NYC(count)>DEN(count)
highDen=highDen+1;
end
count=count+1;
end
fprintf('\nDuring %g days, the temprature in Denver was higher than the temprature in New York city.\n',highDen);
end
%output
check the attachment for additional Information
Answer:
a
The rate of radiation of the energy is
b
The irradiation is
c
The amount of energy absorbed is
d
The oak Tree would catch fire because the temperature of the blast(7200 K) is higher than the flammability limit (650 K) of the oak tree and secondly the thickness is very small
Explanation:
From the question we are told that
The temperature is
The diameter of the ball is
Hence the radius =
The total energy radiated can be mathematically represented as
Where is the Stefan-Boltzmann constant
A is the area of a sphere =
Substituting values we have
Now the state of the energy is mathematically represented as
A sketch illustrating the b part of the question is shown on the first uploaded image
looking at the height at which the blast occurs(16km) as compared to the height of the wall we notice that the height of the wall is negligibly small
from the diagram x can be calculated as follows
This value of x represents the radius of the blast(assuming it is spherical ) when it is at that wall
Now the irradiation G is mathematically represented as
Here r = 43.0813 Km = 43.0813 × 1000 = 43081.3 m
Generally the amount of energy absorbed can be mathematically represented as
Where t is the time taken
Therefore
