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LUCKY_DIMON [66]
3 years ago
9

Why do bridges collapse?

Engineering
2 answers:
Reika [66]3 years ago
8 0

Hi! bridges could have been collapse due to an error made by the engineers during construction.

liraira [26]3 years ago
7 0

Answer:

A substantial proportion of bridge accidents occur during the bridge's construction. These mishaps are frequently caused by an engineering error, such as a miscalculation. The bridge collapses under its own weight, which can be fatal to the employees who are working on it at the moment.

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What is a plaster ratio?​
Makovka662 [10]
Plaster Mix Ratio
Mix cement and sand in the ratio of 1:6 (1 cement:6 sand) for inner plastering of bricks. And for outer plastering mix it in the ratio of 1:4. On a brick wall never do plastering of thickness more than 12 or 15mm. At one go, avoid plastering of more than 12mm thickness.

6 0
3 years ago
A 10-ft-long simply supported laminated wood beam consists of eight 1.5-in. by 6-in. planks glued together to form a section 6 i
ruslelena [56]

Answer:

point B where Q_B = 101.25 \ in^3  has the largest Q value at section a–a

Explanation:

The missing diagram that is suppose to be attached to this question can be found in the attached file below.

So from the given information ;we are to determine the  point that  has the largest Q value at section a–a

In order to do that; we will work hand in hand with the image attached below.

From the image attached ; we will realize that there are 8 blocks aligned on top on another in the R.H.S of the image with the total of 12 in; meaning that each block contains 1.5 in each.

We also have block partitioned into different point segments . i,e A,B,C, D

For point A ;

Let Q be the moment of the Area A;

SO ; Q_A = Area \times y_1

where ;

y_1 = (6 - \dfrac{1.5}{2})

y_1 = (6- 0.75)

y_1 = 5.25 \  in

Q_A =(L \times B)  \times y_1

Q_A =(6 \times 1.5)  \times 5.25

Q_A =47.25 \ in^3

For point B ;

Let Q be the moment of the Area B;

SO ; Q_B = Area \times y_2

where ;

y_2 = (6 - \dfrac{1.5 \times 3}{2})

y_2= (6 - \dfrac{4.5}{2}})

y_2 = (6 -2.25})

y_2 = 3.75 \ in

Q_B =(L \times B)  \times y_1

Q_B=(6 \times 4.5)  \times 3.75

Q_B = 101.25 \ in^3

For point C ;

Let Q be the moment of the Area C;

SO ; Q_C = Area \times y_3

where ;

y_3 = (6 - \dfrac{1.5 \times 2}{2})

y_3 = (6 - 1.5})

y_3= 4.5 \  in

Q_C =(L \times B)  \times y_1

Q_C =(6 \times 3)  \times 4.5

Q_C=81 \ in^3

For point D ;

Let Q be the moment of the Area D;

SO ; Q_D = Area \times y_4

since there is no area about point D

Area = 0

Q_D =0 \times y_4

Q_D = 0

Thus; from the foregoing ; point B where Q_B = 101.25 \ in^3  has the largest Q value at section a–a

3 0
4 years ago
In which equation is y a nonlinear function of x
Goshia [24]
Where are the equations?
5 0
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when testing transistors, how much minimum voltage difference should be seen across the base-emitter junction? A. 0.1 VDC B. 0.4
dolphi86 [110]

Answer:

0.9VDC

Explanation:

When testing transistors, it is important to use 0.9 VDC minimum voltage difference across the base-emitter junction.

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We can recycle glass as many time as we want. a)-True b)-False
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Answer: True

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3 years ago
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