Answer:
The correct answer is
option C. current to pneumatic (V/P)
Explanation:
A current to pneumatic controller is basically used to receive an electronic signal from a controller and converts it further into a standard pneumatic output signal which is further used to operate a positioner or control valve. These devices are reliable, robust and accurate.
Though Voltage and current to pressure transducers are collectively called as electro pneumatic tranducers and the only electronic feature to control output pressure in them is the coil.
The flow of power cannot be reversed since the slider could not move the worm gears. Since the input has one continuous tooth and the output has not teeth there is no gear ratio and no change in torque and speed.
because not all substances react the same to temperature changes. If you heat a metal and an organic substance and you turn the temperature up, the organic substance like water will react (boil) while most metals need higher temperature to react.
Answer:
Explanation:
All answers have been attached as files please check.
Answer:
The answer is "150
".
Explanation:
Its line length must be converted into wavelengths for the Smith chart to be used.
![\to \beta = \frac{2 \pi }{\lambda } \\\\\to u_p = \frac{\omega }{\beta}\\\\\lambda =\frac{2 pi}{\beta} =\frac{2 \pi U_p}{\omega}=\frac{c}{\sqrt{\varepsilon_r f}}](https://tex.z-dn.net/?f=%5Cto%20%5Cbeta%20%20%3D%20%5Cfrac%7B2%20%5Cpi%20%7D%7B%5Clambda%20%7D%20%5C%5C%5C%5C%5Cto%20u_p%20%3D%20%5Cfrac%7B%5Comega%20%7D%7B%5Cbeta%7D%5C%5C%5C%5C%5Clambda%20%3D%5Cfrac%7B2%20pi%7D%7B%5Cbeta%7D%20%3D%5Cfrac%7B2%20%5Cpi%20U_p%7D%7B%5Comega%7D%3D%5Cfrac%7Bc%7D%7B%5Csqrt%7B%5Cvarepsilon_r%20f%7D%7D)
![= \frac{3 \times 10^8}{ 2.25 \times (5 \times 10^9)}\\\\= \frac{3}{ 2.25 \times 5\times 10 }\\\\= \frac{3}{ 22.5 \times 5 }\\\\= \frac{3}{ 112.5}\\\\= 0.04 \ m.](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B3%20%5Ctimes%2010%5E8%7D%7B%202.25%20%5Ctimes%20%20%285%20%20%5Ctimes%2010%5E9%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B3%7D%7B%202.25%20%5Ctimes%20%205%5Ctimes%2010%20%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B3%7D%7B%2022.5%20%5Ctimes%20%205%20%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B3%7D%7B%20112.5%7D%5C%5C%5C%5C%3D%200.04%20%5C%20m.)
![l =\frac{0.30 }{0.04 } \times \lambda](https://tex.z-dn.net/?f=l%20%3D%5Cfrac%7B0.30%20%7D%7B0.04%20%7D%20%5Ctimes%20%5Clambda)
![= 7.5 \lambda](https://tex.z-dn.net/?f=%3D%207.5%20%5Clambda)
Because it is an integrated half-wavelength amount,
![Z_{in} = Z_L = 150 \ \Omega](https://tex.z-dn.net/?f=Z_%7Bin%7D%20%3D%20Z_L%20%3D%20150%20%5C%20%5COmega)