1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stich3 [128]
2 years ago
5

In a medical lab, Sandrine is working to isolate one element from a sample of liquid material. She uses a centrifuge, a machine

with a super-fast
rotating container in its center. This is an example of what applied process?
OA mass and heat transfer
OB. convection
OC separation
OD. biomechanics
Engineering
1 answer:
Ludmilka [50]2 years ago
4 0

Answer:

1

Explanation:

You might be interested in
Technician A says that carbon monoxide (CO) and hydrocarbon (HC) levels should increase if the air injection reactor (AIR) hoses
lara31 [8.8K]

Answer:Technician A

Explanation:

7 0
4 years ago
Read 2 more answers
Compare and contrast ""centralized"" and ""decentralized"" routing algorithms. (What are the advantages and disadvantages of eac
pantera1 [17]

Answer:

Comparison between centralized and decentralized routing algorithms:

The major similarity between both centralized and decentralized routing algorithms is that they are both communication serving systems. They both utilize node system(e.g, computer) and are both a communication liking system( e.g, Cable).

Contrasting between centralized and decentralized routing algorithms:

There are few differences between these two type of communication link or path way system but to name a couple of them,

For centralized, there is a single client server distribution node which simply means that one or more client server system are connected to a central processing server.

This also means that if the central processing server or pathway fails, it leads to the failure of the entire system. That is, there is no sending, responding or general processing of any form of requests. Example of a system that uses the centralized routing algorithm is the google search engine.

WHILE:

for the decentralized routing algorithms, there are multiple client server distribution pathway and each server makes its own decision. Here,there is no single entity that receives and responds to the request therefore,failure of any form of central path way processing node does not lead to the failure of the whole system unlike for the centralized system.

Advantages of centralized routing algorithm:

It can be easily protected or secured due to the nature of the system. If the central node is been secured, it generally translate to the different client node being secured.

It is easy to disconnect a connected client node from the central pathway node or central server as the case may be.

Disadvantages of centralized routing algorithm:

The client nodes are totally dependent on the central node or server so if there is a failure in the central server, the client node is then totally shut down.

Advantages of decentralized routing algorithm:

There is a random distribution of data on all the processing node or server which automatically creates a form of balance within the system. This leads to minimal or no down time processing client request.

Disadvantages of decentralized routing algorithm:

Due to the nature or fact that there are multiple processing system for different client node, it is difficult to detect which client node or request processing server is faulty. This can lead to delay in the fixing of fault in the system should it arise.

Why do we prefer a ""decentralized"" algorithm for routing messages through the internet?

The major reason why decentralized algorithm routing is preferred is because of the level of security attached to it. Each processing servers are secured independently and there is privilege of utilizing independent networking system.

5 0
3 years ago
An inductor is connected to a voltage source and it is found that it has a time constant, t. When a 10-ohm resistor is placed in
prisoha [69]

Answer:

A) 30 mH

B ) 10-ohm

Explanation:

resistor = 10-ohm

Inductor = 30mH ( l )

L = inductance

R = resistance

r = internal resistance

values of the original Inductors

Note : inductor = constant time (t)  case 1

inductor + 10-ohm resistor connected in series = constant time ( t/2) case2

inductor + 10-ohm resistor + 30 mH inductance in series = constant time (t) case3

<em>From the above cases</em>

case 1 = time constant ( t ) = L / R

case 2 = Req = R + r hence time constant  t / 2  = L / R + r  therefore

t = \frac{2L}{R+r}

case 3 = Leq = L + l , Req = R + r .  constant time ( t )

hence Z = \frac{L + l}{R + r} = t

A) Inductance

To calculate inductance equate case 1 to case 3

\frac{L}{R} = \frac{L + l}{R + r} =   L / 10 = (L + 30) / ( 10 + 10 )

= 20 L = 10 L + 300 mH

   10L = 300 m H

therefore L = 30 mH

B ) The internal resistance

equate case 1 to case 2

\frac{L}{R} = \frac{2L}{R + r}

R + r = 2 R  therefore  ( r = R )   therefore internal resistance = 10-ohm

6 0
3 years ago
Which of the following are true about algorithms? (You may select more than one)
r-ruslan [8.4K]
Have a orderf. Fr

R
F
F
D
Djeiiekee
7 0
3 years ago
Read 2 more answers
he desk has a weight of 80 lb and a centerof gravity at G. Determine the initial acceleration of a desk when the man applies eno
-BARSIC- [3]

Answer:

N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb

Explanation:

Na and Nb are the vertical reactions on each of the two legs at A and at B

For the horizontal forces:

Fcos(30)-0.5N_a-0.5N_b=0\\0.5N_a+0.5N_b= Fcos(30)\\N_a+N_b= 2Fcos(30)

For the vertical forces:

N_a+N_b-Fsin(30)-75=0\\N_a+N_b=Fsin(30)+80

Therefore equating both equations:

2Fcos(30)=Fsin(30)+80\\F(2cos(30)-sin(30))=80\\F=\frac{80}{2cos(30)-sin(30)} =64.93N

After the desk star to slide:

sum of all vertical force = ma , therefore:

N_a+N_b-64.93sin(30)-80=0\\N_a+N_b=64.93sin(30)+80

sum of all horizontal force = ma

64.93cos(30)-0.2N_a-0.2N_b=\frac{80lb}{32.2ft/s^2}a\\ 0.2(N_a+N_b)=64.93cos(30)-\frac{80lb}{32.2ft/s^2}a\\N_a+N_b=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}a}{0.2}=324.65-12.42a

equating both equations:

324.65-12.42a=64.93sin(30)+80\\12.42a=324.65-64.93sin(30)-80\\12.42a=212.185\\a=17.08ft/s^2

From the moment equation:

4N_b-80(2)-64.93(3)=\frac{-80}{32.2} (17.08)(2)\\N_b=67.48lb

N_a=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}(17.08)}{0.2}-67.48 = 45.04lb

For each leg: N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb

7 0
3 years ago
Other questions:
  • Astronauts who landed on the moon during the Apollo 15, 16, and 17 missions brought back a large collection of rocks to the eart
    6·1 answer
  • Occurs between a tire on a vehicle and the roadway when a wall of water separates the tire from
    15·1 answer
  • You're running an engine and seeing that it is exhausting blue smoke. Which is likely to
    9·1 answer
  • Who developed the process of blueprinting?
    12·1 answer
  • Given below are the measured streamflows in cfs from a storm of 6-hour duration on a stream having a drainage area of 185 mi^2.
    11·1 answer
  • Does red and a lot of more red make blue
    8·2 answers
  • How is a scale model different from other types of models?
    12·1 answer
  • Cho biết tác dụng chung của các hệ giằng khung ngang nhà công nghiệp nhẹ 1 tầng 1 nhịp.
    13·1 answer
  • What is the primary responsibility of ABET?
    13·1 answer
  • Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!