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wlad13 [49]
3 years ago
10

Nevermind for this one!

Chemistry
1 answer:
Simora [160]3 years ago
8 0

Answer:

ty :D

Explanation:

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Why is the symbol for the element sulfur and the formula for a molecule of sulfur differ
lukranit [14]

Answer:

Sulfur (S) is an element while the formula for this element is not just sulfur (e.g. H2S, SO2)

Explanation:

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In order to improve their recovery after an intense workout many high-level athletes do "cool downs" to slow their movements, ea
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This question is so confusing, I'm sorry

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Which of the following has the lowest Ka?a. carbonic acid b. dihydrogen phosphate c. phosphoric acid d. bicarbonate
Naya [18.7K]

Explanation:

A compound or molecule which will have least dissociation and that is not able to given hydrogen ion easily upon dissociation will also have a low value of K_{a}.

Dissociation of the given compounds or species will be as follows.

 H_{2}CO_{3} \rightleftharpoons H^{+} + HCO^{-}_{3}

 H_{2}PO^{-}_{4} \rightleftharpoons H^{+} + HPO^{-}_{4}

 H_{3}PO_{4} \rightleftharpoons H_{+} + H_{2}PO^{-}_{4}

As, chemical formula of bicarbonate is HCO^{-}_{3} and due to the presence of a negative charge it is difficult to lose a positively charged hydrogen ion. This is because oppositely charged ions will be bonded by strong force of attraction.

Hence, it will not easily lose a hydrogen ion due to which bicarbonate has the lowest K_{a}.

Thus, we can conclude that out of the given species bicarbonate has the lowest K_{a}.    

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3 years ago
5. Which are forms of energy? Select all that apply.
notsponge [240]

Answer:

Chemical

Explanation:

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5 0
3 years ago
Read 2 more answers
When a 18.0 mL sample of a 0.308 M aqueous hydrofluoric acid solution is titrated with a 0.361 M aqueous sodium hydroxide soluti
sleet_krkn [62]

Answer:

pH = 12.8

Explanation:

HF + NaOH → F⁻ + Na⁺ + H₂O

<em>1 mole of HF reacts with 1 mole of NaOH</em>

<em />

Initial moles of HF and NaOH are:

HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF

NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH

That means moles of NaOH remains after reaction are:

8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>

Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L

Molar concentration of NaOH is

2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]

pOH = - log [OH⁻] = 1.17

As pH = 14 - pOH

<em>pH = 12.8</em>

<em></em>

4 0
3 years ago
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