Answer:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Explanation:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Balanced chemical equation:
3HNO₃ + Al(OH)₃ → Al(NO₃)₃ + 3H₂O
Ionic equation:
3H⁺ + 3NO⁻₃(aq) + Al(OH)₃(s) → Al³⁺(aq) + 3NO₃⁻¹(aq) + 3H₂O(l)
Net ionic equation:
Al(OH)₃(s) + 3H⁺(aq) → Al³⁺(aq) + 3H₂O(l)
The NO⁻₃ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
The correct answer is: [C]:
___________________________________________________________
"<span>pressure and the number of gas molecules are directly related."
___________________________________________________________
<u>Note</u>: The conclusion was: "</span> as the pressure in a system increases, the number of gas molecules increases" — over the course of many trials.
This means that the "pressure" and the "number of gas molecules" are directly related.
Furthermore, this conclusion is consistent with the "ideal gas law" equation:
" PV = nRT " ;
____________________________________________________________
in which:
"P = Pressure" ;
"n = number of gas molecules" ;
___________________________________________________________
All other factors held equal, when "n" (the "number of gas molecules")
increases in value (on the "right-hand side" of the equation), the value for "P" (the "pressure" — on the "left-hand side" of the equation), increases.
___________________________________________________________
Answer:
37 mmol of acetate need to add to this solution.
Explanation:
Acetic acid is an weak acid. According to Henderson-Hasselbalch equation for a buffer consist of weak acid (acetic acid) and its conjugate base (acetate)-
![pH=pK_{a}(acetic acid)+log[\frac{mmol of CH_{3}COO^{-}}{mmol of CH_{3}COOH }]](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%28acetic%20acid%29%2Blog%5B%5Cfrac%7Bmmol%20of%20CH_%7B3%7DCOO%5E%7B-%7D%7D%7Bmmol%20of%20CH_%7B3%7DCOOH%20%7D%5D)
Here pH is 5.31,
(acetic acid) is 4.74 and number of mmol of acetic acid is 10 mmol.
Plug in all the values in the above equation:
![5.31=4.74+log[\frac{mmol of CH_{3}COO^{-}}{10}]](https://tex.z-dn.net/?f=5.31%3D4.74%2Blog%5B%5Cfrac%7Bmmol%20of%20CH_%7B3%7DCOO%5E%7B-%7D%7D%7B10%7D%5D)
or, mmol of
= 37
So 37 mmol of acetate need to add to this solution.
Answer:
True, in as far as greater magnitude = greater power.