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scoray [572]
2 years ago
13

Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh

ow all your work.
Chemistry
1 answer:
Svet_ta [14]2 years ago
3 0

Answer: The freezing point depression is 1.86^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=K_f\times m

\Delta T_f = Depression in freezing point

K_f = freezing point constant = 1.86^0C/m

m= molality = \frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m

\Delta T_f=1.86mol/kg^0C\times 1m  

\Delta T_f=1.86^0C  

Thus freezing point depression is 1.86^0C

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