Question

Somebody help me please!!!!!!!!!

Answer 1

Answer:

$(x-5)^2+(y+3)^2=10$

Step-by-step explanation:

equation of a circle: (x – h)^2 + (y – k)^2 = r^2 where (h,k) is the center

The center of the circle is at (5, -3)

(x-5)^2+(y+3)^2

To find the radius, use distance formula: $\sqrt{(x_{1}-x_{2})^2 + (y_{1}-y_{2})^2}$

$\sqrt{(6-5)^2 + (3)^2}$

$\sqrt{1^2 + 3^2} = \sqrt{1+9} = \sqrt{10}$

$(x-5)^2+(y+3)^2=10$