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Lyrx [107]
3 years ago
11

g According to the Third Law, the action and reaction forces are exactly equal in magnitude and in opposite directions. So when

a horse pulls a cart, the cart pulls the horse with the same force. Why then does the cart move
Physics
1 answer:
torisob [31]3 years ago
7 0

Answer:

One way to look at this is to consider the forces acting on any point in a string.

For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.

One generally considers the net force acting on the center of mass of an object not  the individual forces acting on each infinitesimal mass composing

the object.

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A large mass collides with a stationary, smaller mass. How will the masses behave if the collision is inelastic?
Mamont248 [21]
Most likely they would stick together and keep moving together
7 0
3 years ago
Read 2 more answers
What kind of variation is there in the mechanical energy as the cart rolls down the ramp? Does this agree with your prediction?
Harlamova29_29 [7]

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         W_{nc} = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

6 0
3 years ago
Whenever a charged particle encounters a magnetic field, the particle tends to spiral around the magnetic field lines. as it doe
fomenos
The electromagnetic radiation produced when a charged particle moves spirally in a magnetic field is called <span>synchrotron radiation. This phenomenon occurs due to the fact the particle is accelerated radially (due to the presence of the magnetic field), and every charged particle when it is accelerated emits electromagnetic radiation.</span>
4 0
3 years ago
Which force acts on the plane at a distance?
shutvik [7]

Answer:

gravity

Explanation:

6 0
3 years ago
(1 point) Answer the following questions about the sphere whose equation is given by x2+y2+z2−4x+4y=73. x2+y2+z2−4x+4y=73. 1. Fi
pychu [463]

Answer:

R=9.

C=(2,-2,0).

Explanation:

Lets try to find how x^2+y^2+z^2-4x+4y=73 can be written in the form of (x-a)^2+(x-b)^2+(x-c)^2=R^2, since then its radius R and center of coordinates C=(a,b,c) would be easily recognizable.

Since we have the terms -4x and +4y, they seem to have come from the terms (x-2)^2 and (y+2)^2, and we would need to take care of the extra +4 by substracting then. More explicitly:

(x-2)^2-4=x^2-4x+4-4=x^2-4x, as we had originally with the x terms

(y+2)^2-4=y^2+4y+4-4=y^2+4y, as we had originally with the y terms

Which means:

x^2-4x+y^2+4y+z^2=(x-2)^2-4+(y+2)^2-4+z^2

Or, putting all together:

(x-2)^2-4+(y+2)^2-4+z^2=73

(x-2)^2+(y+2)^2+z^2=9^2

So our radius is 9 and the center is (2,-2,0).

5 0
3 years ago
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