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sineoko [7]
3 years ago
14

A simple pendulum consists of a small object with mass m = 1.91 kg and a massless string with length l = 1 m. Halfway down the s

tring from the hanging spot, there is a peg which causes the string to bend. Find the period of this pendulum, in second.
Physics
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

around the coop

Explanation:

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ozzi

Answer:

The angular velocity produced is 0.321 rad/s.

Explanation:

Given :

Diameter of space station , D = 190 m.

Therefore, radius , R=\dfrac{D}{2}=\dfrac{190}{2}=95\ m.

Also, acceleration , a=9.8\ m/s^2.

We know, angular velocity , \omega=\sqrt \dfrac{a}{R}.

Putting value of g and R in above equation.

We get ,

\omega=\sqrt \dfrac{9.8\ m/s^2}{95\ m}

\omega=0.321\ rad/s.

Hence, this is the required solution.

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