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Lilit [14]
3 years ago
13

A block of mass m = 2.0 kg slides head on into a spring of spring constant k = 260 N/m. When the block stops, it has compressed

the spring by 14 cm. The coefficient of kinetic friction between block and floor is 0.42. While the block is in contact with the spring and being brought to rest, what are
(a) the work done by the spring force and
(b) the increase in thermal energy of the block-floor system?
(c) What is the block's speed just as the block reaches the spring? Please show all steps.
Physics
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

a) Ws = 2.548 J

b) Wf = 1.153 J

c) v = 1.923 m / s

Explanation:

a) The work done by the spring force  

Ws =  ½ * k * x²

Ws =  ½ * 260 N/m *0.14² m  

Ws =  2.548J

b) The increase in thermal energy can by find using  

Et = Wf

Wf = µ * m *g * x  

Wf = 0.42 * 2.0 kg *9.8 m/s² * 0.14m

Wf = 1.153 J

c) The speed just as the block reaches can by fin using

EK = Ws + Et

Ek = ( 2.548 + 1.153 ) J = 3.7 J

Ek = ½ * m * v²

v² = 2* Ek / m

v = √[2 * 3.7 J / 2.0 kg]

v = 1.923 m / s

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d1i1m1o1n [39]

Answer:

Net force, F = 44.66 N

Explanation:

It is given by,

Initial velocity of the person, u = 0

Final velocity of the person, v = 0.68 m/s

Distance, s = 0.428 m

Combined mass of the person and the kayak, m = 82.7 kg

We need to find the net force acting on the kayak i.e.

F = ma...........(1)

Firstly, we will calculate the value of "a" from third equation of motion as :

v^2-u^2=2as

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(0.68\ m/s)^2-0}{2\times 0.428\ m}

a=0.54\ m/s^2

Put the value of a in equation (1) as :

F=82.7\ kg\times 0.54\ m/s^2

F = 44.66 N

So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.

6 0
3 years ago
Dose sound travel faster in a warm room or a cold room? explain your answer
dusya [7]

Answer:Sound travel faster in warm room.

Explanation:The speed of sound depends on the temperature of the medium. Mathematically, the relation between the speed of the sound and the temperature is give by:v=

is the ratio of the specific heats

R is the gas constant

T is the temperature of the medium

We know that the temperature of the warm room is more as compared to the cold room.

So, it is clear that the sound travel faster in a warm room. The particles move faster when the temperature is high.            

8 0
3 years ago
El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una corr
Solnce55 [7]

La respuesta correcta para esta pregunta abierta es la siguiente.

No incluyes opciones, incisos, o alguna referencia específica para responder esta pregunta.

De ahí que responderemos en términos generales basándonos en nuestro conocimiento previo.

El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una correcta asociación la cual sería benéfica para ambos campos de conocimiento porque de esta manera se estarían complementando y enriqueciendo el uno al otro.

Cuando la ciencia -en este caso, la cosmología- acepte los conceptos metafísico que no tienen un sustento científico pero que sí contemplan alternativas en el mundo espiritual que son aceptadas por una innumerable cantidad de personas, entonces los expertos podrán plantear nuevas y diferentes posibilidades de entender los fenómenos que al día de hoy, carecen de una convincente explicación.

Tanto la cosmología como la metafísica podrían mostrarse más receptivos a las aportaciones de una y la otra, con objeto de poder aumentar las posibilidades de comprender un fenómeno. No necesariamente debe haber una teoría científica para poder avanzar en el conocimiento de algún tema. De ahí que las aportaciones metafísicas sean válidas como una alternativa de investigación.

5 0
2 years ago
A rocket at rest with a mass of 942 kg is acted on by an average net force of 6,731 N upwards for 21 s. What is the final veloci
Galina-37 [17]

Answer:

Explanation:

Givens

m = 942

F = 6731

t = 21 seconds

vi = 0

vf = ?

Formula

F = m * (vf -  vi )  / t

Solution

6731 = 942*(vf - 0)/21          Multiply both sides by 21

6731 * 21 = 942*vf

141351 = 942*vf                   Divide by 942

141351/942 = vf

vf = 151 m/s

6 0
2 years ago
Two moles of helium are initially at a temperature of 21.0 ∘Cand occupy a volume of 3.30×10−2 m3 . The helium first expands at c
Anettt [7]

Answer:

(B) The total internal energy of the helium is 4888.6 Joules

(C) The total work done by the helium is 2959.25 Joules

(D) The final volume of the helium is 0.066 cubic meter

Explanation:

(B) ∆U = P(V2 - V1)

From ideal gas equation, PV = nRT

T1 = 21°C = 294K, V1 = 0.033m^3, n = 2moles, V2 = 2× 0.033=0.066m^3

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∆U = 148140.4(0.066 - 0.033) = 4888.6 Joules

(C) P2 = P1(V1÷V2)^1.4 =148140.4(0.033÷0.066)^1.4= 148140.4×0.379=56134.7 Pascal

Assuming a closed system

(C) Wc = (P1V1 - P2V2) ÷ 0.4 = (148140.4×0.033 - 56134.7×0.066) ÷ 0.4 = (4888.6 - 3704.9) ÷ 0.4 = 1183.7 ÷ 0.4 = 2959.25 Joules

(C) Final volume = 2×initial volume = 2×0.033= 0.066 cubic meter

6 0
3 years ago
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