Question

If f(x) = x^2-1 which of the following ordered pairs would be on the graph of f(x)

Answer 1

These following ordered pairs are on the graph:

• (0,1)
• (5, 24)
• (-2,3)

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An ordered pair (x, f(x)) will be on the graph if replacing them into the equation, we get an equivalence.

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The equation is:

$f(x) = x^2 - 1$

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(0,1)

Here, we test $x = 0, f(x) = 1$

Replacing into the equation:

$1 = 0^2 - 1$

$1 = -1$

False, so not on the graph.

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(0,1)

Here, we test $x = 1, f(x) = 0$

Replacing into the equation:

$0 = 1^2 - 1$

$0 = 0$

True, so on the graph.

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(3,5)

Here, we test $x = 3, f(x) = 5$

Replacing into the equation:

$5 = 3^2 - 1$

$5 = 8$

False, so not on the graph.

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(5,24)

Here, we test $x = 5, f(x) = 24$

Replacing into the equation:

$24 = 5^2 - 1$

$24 = 24$

True, so on the graph.

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(-2,3)

Here, we test $x = -2, f(x) = 3$

Replacing into the equation:

$3 = (-2)^2 - 1$

$3 = 3$

True, so on the graph.

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(-4,-17)

Here, we test $x = -4, f(x) = -17$

Replacing into the equation:

$-17 = (-4)^2 - 1$

$-17 = 15$

False, so not on the graph.

A similar question is given at brainly.com/question/2102317