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3 years ago

A triangle with side lengths of 32, 60 and 68 is a right triangle? true or false

Mathematics

2 answers:

Troyanec [42]3 years ago

5 0

I believe that it would come out to become true

tia_tia [17]3 years ago

3 0

Answer:

true

Step-by-step explanation:

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D=1/3fk, solve for f

Stella [2.4K]

Answer:

f=3d/k

Step-by-step explanation:

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3 years ago

5/7 = x/11 round your answer to the nearest tenth.

Scilla [17]

Answer:

7.9

Step-by-step explanation:

Multiply both sides of the equation by 11. This cancels out the fraction so 11 * 5/7 = x

lmk if I misunderstood the question or need to elaborate

6 0

3 years ago

Read 2 more answers

The ratio of girls to boys in the 6th grade is to 6to7 how many girls are there if there are 364total students

Rina8888 [55]

Answer:

168 girls.

Step-by-step explanation:

There are a total of 6 + 7 = 13 'parts'.

So one part = 364 / 13 = 28.

So the number of girls = 6 * 28

= 168.

4 0

2 years ago

Y=0.5x+3.5 on graphs

tresset_1 [31]

You should go up 3.5 on the Y-Axis and then go up .5 and over 1.

5 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$