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3 years ago

5. Give one word answers:

Computers and Technology

1 answer:

sesenic [268]3 years ago

8 0

Answer:

a. application software

b. 128 megabytes

c. trade and commerce

d. third generation

e. Nws super computers

Explanation:

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The benefits for a cad proram is: (points : 2) 1 accuracy 2 repeatability 3 simplicity 4 all of the above

NARA [144]

ALL OF THE ABOVE. The benefits for a CAD program is accuracy, repeatability, simplicity.

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2 years ago

Monica is writing a paper, and it needs to contain a certain amount of words. What Word Online feature can she use?IndentingProo

Greeley [361]

Answer:

Its word count so she knows how much words she is writing

Explanation:

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2 years ago

Match the components of a blog to their descriptions.

motikmotik

Answer:

Explanation:

1. entry title - name of the posting

2. permalink - place where a blog posting is located

3. entry date - when the posting became available

4. comment - allows users to add to the conversation

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2 years ago

The cost to ship a package is a flat fee of 75 cents plus 25 cents per pound.

Sonbull [250]

Answer:

The following alterations are done to the program

1. Replace /* Your solution goes here */ with

const int CENTS_PER_POUND = 25;

cout<<"Ship Weight Pounds: ";

cin>>shipWeightPounds;

2. Include

shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;

after

cout << ", Cents per lb: " << CENTS_PER_POUND;

Explanation:

See attachment for complete program as it should be ordered

This line declares CENTS_PER_POUND as a constant integer and it also initializes the variable to 25

const int CENTS_PER_POUND = 25;

This prompts the user for the weight of the shipping items (in pounds)

cout<<"Ship Weight Pounds: ";

This gets user input for the weight of the shipping item

cin>>shipWeightPounds;

.............................

........

...

This calculates the cost of shipping the item

shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;

Download cpp

6 0

2 years ago

What is the output of the following code? stackList stack; int x, y; x = 2; y = 3; stack.push(8); stack.push(x); stack.push(x +

Sunny_sXe [5.5K]

Stack is LIFO data structure (Last In First Out) where the last element entered in stack will be the last one to be out of stack. It has three operations: push() : used to insert an element in stack, pop() : used to delete an element from the stack, top() : used to return the top of the stack i.e. the newest member of the stack. All these operations will take place at the top.

Explanation:

Now, looking at the program, x and y are initialized the values of 2 and 3 respectively. The stack pushes 8 onto the stack making it the first member of the stack. Then the value of x which is 2 is pushed onto the stack. Next, (x+5) = (2+5) = 7 is pushed onto the stack.

Pop() is used to delete hence 7 is popped out from the stack. top() is assigned to y which is 2 in this case and again 2 is popped out from the stack. Now, (x+y) = (2+2) = 4 is pushed onto the stack. And the top() is assigned to x which is 4. 4 is again popped out from the stack. Hence the value of x is 4.

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3 years ago