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Arte-miy333 [17]
3 years ago
6

Answer ASAP please! …

Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

"A" seems to be incorrect....

Step-by-step explanation:

"A" seems to be incorrect....

\frac{\left(\sin \left(60^{\circ \:}\right)\cdot \:300\right)}{\sin \left(90^{\circ \:}\right)}=150\sqrt{3}\quad \begin{pmatrix}\mathrm{Decimal:}&259.80762\dots \end{pmatrix}

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Which of the following statements best describes the graph of -5x+2y=1
ahrayia [7]
The answer is the third option.
x and y are both to the first degree so we know it makes a straight line.
Next check the ordered pairs to see which set are true in the equation.
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Answer:

48

Step-by-step explanation:

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Helpppp Pleaseee....​
NeX [460]

Answer:

\frac{4 \sqrt{10} }{5}

Step-by-step explanation:

\frac{8}{ \sqrt{10} }  \times  \frac{ \sqrt{10} }{ \sqrt{10} }

\frac{8 \sqrt{10} }{ {\sqrt{10}}^{2}  }

\frac{8 \sqrt{10} }{10}

\frac{4 \sqrt{10} }{5}

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1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti
uysha [10]

Answer:

1) 0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

b) ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=0.0826052 represent the sample mean

\mu population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size  

Part 1

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=5-1=4

The Confidence level is 0.95 or 95%, and the significance would be \alpha=0.05 and \alpha/2 =0.025, the critical value would be using the t distribution with 4 degrees of freedom: t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

Part 2

The original margin of error is given by:

ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

3 0
3 years ago
Determine the margin of error, m , of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume
madreJ [45]

Answer:

E= 6.45

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

Step-by-step explanation:

Margin error is the value that is lie above and below the sample.It gives percentage of numbers.Its is the product of critical value standard deviation and standard error of statistic.

General formula for the margin of error is

Margin of error = critical value  ×   standard error of statistic

                        = z \alpha /2  ×   σ √n

z-value from two tailed is listed below:

From the table of standard normal distribution, probability value of 0.10.

row and column values gives the area to the two tail of z.

The positive z value is 2.58.

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

after putting these vales we obtain the margin of error value that is

E= 6.45

7 0
3 years ago
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