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lisabon 2012 [21]

2 years ago

15

PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

1 answer:

Aneli [31]2 years ago

4 0

Maria first made an error in step 3.

Maria can correct her error by multiplying 136.49 by 1 over 4 before subtracting 3.0625 from it.

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Stan made 24 sales in 6 hours what is the ratio of sale to hours?

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24 (sales) / 6 (hours)
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3 years ago

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One way to increase acceleration is by

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D. Increasing both force and mass equally

Step-by-step explanation:

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3 years ago

How many different ways can a kite be reflected across a line of symmetry so that it carries onto itself?

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2 years ago

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A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

$P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.$

Then

$P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}$

$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

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2 years ago

Solve for x<br> 3 (x- 4) = 44 - 5x<br> A: 4<br> B: 5<br> C: 6<br> D: 7

neonofarm [45]

D x would equal seven

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3 years ago