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Aliun [14]
3 years ago
7

Evaluate the exponential expression (−2)6.

Chemistry
1 answer:
Olegator [25]3 years ago
6 0

A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

If you want to learn more, you can read:

brainly.com/question/17172630

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3 years ago
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What is the ph of a (6.00x10^-3) m hi solution?
KatRina [158]
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[H+] = [HI]
[H+] = 6 × 10^-3 M

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5 0
3 years ago
Which of these mixtures will MOST LIKELY result in soil? A) sand, clay, and heat B) sand, clay, and water C) sand, clay, heat, a
Wewaii [24]

Answer:

I think it should be C.

Explanation:

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3 years ago
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What mass of KNO3 would be needed to produce 18.4 liters of oxygen gas, measured at 1.50 x 10^3 kPa and 15 degrees Celsius?
Brut [27]

Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

Temperature T = 15 C + 273 = 288 K

Pressure P = 1.5 x 10^ 3 KPa

We know universal Gas constant R = 8.314 L KPa K-1 mol-1

Using the relation PV = nRT

Number of moles of oxygen gas n = PV / RT

Plugging in the values

n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)

n = 11.527 mol

Now the balanced chemical equation for this reaction is

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From the equation we can see that

1 mol of O2 is produced from 2 mol of KNO3.

∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.

= 23.054 mol of KNO3

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Mass of KNO3 = 23.054 mol x 101 gram / mol

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7 0
3 years ago
The anion formed from an oxygen atom is called a(n)
marta [7]
A. Oxygen ion
I am not sure but that's the right one I think. If I am wrong then I am sorry
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