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Paha777 [63]
2 years ago
9

A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equa

tion
2NiS2+5O2=2NiO+4SO2
If (1.50x10^2) g of NiS2 were reacted with (2.420x10^2) g of O2 what would be the theoretical yield of SO2
Enter in scientific notation
Chemistry
1 answer:
Mice21 [21]2 years ago
4 0

Answer:

Theoretical yield of SO₂ is 1.56 × 10² g

Explanation:

Given data:

Mass of NiS₂ = 1.50 ×10² g

Mass of O₂ = 2.420 ×10² g

Theoretical yield of SO₂ = ?

Solution:

Chemical equation:

2NiS₂ + 5O₂ → 2NiO + 4SO₂

Moles of NiS₂:

Number of moles = mass/ molar mass

Number of moles = 1.50 ×10² g / 122.83 g/mol

Number of moles = 1.22 mol

Moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 2.420 ×10² g / 32 g/mol

Number of moles = 7.56 mol

Now we compare the moles of SO₂ with  NiS₂ and O₂.

                  NiS₂            :      SO₂

                    2                :        4

                   1.22             :       4/2×1.22 = 2.44

                    O₂               :          SO₂

                     5                :           4

                     7.56           :           4/5×7.56 =6.05

Moles of SO₂ produced by NiS₂ are less it will limiting reactant.

Mass of SO₂ = moles × molar mass

Mass of SO₂ = 2.44 mol ×  64.07 g/mol

Mass of SO₂ = 156.33 g

So theoretical yield of SO₂ is 1.56 × 10² g

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When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
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Answer:

Mass of CaCl₂ =  20 g

CaCO is presewnt in excess.

Mass of of CaCO₃ remain unreacted =  7.007 g

Explanation:

Given data:

Mass of calcium carbonate = 25 g

Mass of hydrochloric acid = 13.0 g

Mass of calcium chloride produced = ?

Chemical equation:

CaCO₃ + 2HCl  →  CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

Number of moles of CaCO₃= 25.0 g / 100.1 g/mol

Number of moles of CaCO₃ = 0.25 mol

Number of moles of HCl:

Number of moles of  HCl = Mass /molar mass

Number of moles of HCl = 13.0 g / 36.5 g/mol

Number of moles of HCl = 0.36 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃         :               CaCl₂

                    1                 :               1

                 0.25              :            0.25

                HCl                :                CaCl₂

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

The number of moles of CaCl₂ produced by HCl are less it will be limiting reactant.

Mass of CaCl₂ = moles × molar mass

Mass of CaCl₂ =0.18 mol × 110.98 g/mol

Mass of CaCl₂ =  20 g

The calcium carbonate is present in excess.

                HCl                :                CaCO₃

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

So, 0.18 moles react with 0.36 moles of HCl.

The moles of CaCO₃ remain unreacted = 0.25 -0.18

The moles of CaCO₃ remain unreacted = 0.07 mol

Mass of of CaCO₃ remain unreacted = Moles × molar mass

Mass of of CaCO₃ remain unreacted = 0.07 mol × 100.1 g/mol

Mass of of CaCO₃ remain unreacted =  7.007 g

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