Question

The length of a rectangle is 2 cm less than twice the width. The area of the rectangle is 112 cm2. Find the length and width of the rectangle.

Answer 1

Let breadth be x

• Length=2x-2

We know

$\boxed{\sf Area=Length\times Breadth}$

$\\ \sf\longmapsto 112=x(2x-2)$

$\\ \sf\longmapsto 2x^2-2x-112=0$

$\\ \sf\longmapsto x=-7\:or\:x=8$

• Ignore negative value

Now

$\\ \sf\longmapsto Length=2x-2=2(8)-2=16-2=14$

$\\ \sf\longmapsto Breadth=8$