Answer:


z = 2
Step-by-step explanation:
Given equations are
x - 2y - z = 2
x + 3y - 2z = 4
-x + 2y + 3z = 2
from the given equations the augmented matrix can be written as
![\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-1%3A2%5C%5C1%263%26-2%3A4%5C%5C-1%262%263%3A2%5Cend%7Barray%7D%5Cright%5D)

![=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-1%3A2%5C%5C0%265%26-1%3A2%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)

![=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-1%3A2%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)

![=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26-1-%5Cdfrac%7B2%7D%7B5%7D%3A2%2B%5Cdfrac%7B4%7D%7B5%7D%5C%5C%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)
![=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26%5Cdfrac%7B-7%7D%7B5%7D%3A%5Cdfrac%7B14%7D%7B5%7D%5C%5C%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)

![=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26%5Cdfrac%7B-7%7D%7B5%7D%3A%5Cdfrac%7B14%7D%7B5%7D%5C%5C%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C%5C%5C0%260%261%3A2%5Cend%7Barray%7D%5Cright%5D)

![=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%3A%5Cdfrac%7B14%7D%7B5%7D%2B%5Cdfrac%7B7%7D%7B5%7D%5C%5C%5C%5C0%261%260%3A%5Cdfrac%7B2%7D%7B5%7D%2B%5Cdfrac%7B1%7D%7B5%7D%5C%5C%5C%5C0%260%261%3A2%5Cend%7Barray%7D%5Cright%5D)
So, from the above augmented matrix, we can write


z = 2
The closest option to the actual answer is a.
1 5/18 is the actual answer.
If you make both the denominators the same, then you can actually add the fractions together.
To make both of the denominators the same, you need to multiply 5/6 by 9 and 4/9 by 6, which would result in 45/54 + 24/54= 69/54 = 23/18. If we convert it to a mixed fraction, it would result into 1 5/18.
Answer:
Parker will have to pay $31 in a month in which he downloaded 50 songs.
Total amount Parker will pay for s songs = 6 + 0.50s
Step-by-step explanation:
Cost per month = $6
Cost of Offline download = $0.50 per song
A. How much total money would
Parker have to pay in a month in which he downloaded 50 songs?
Total amount Parker will pay = $6 + $0.50(50)
= 6 + 25
= $31
Parker will have to pay $31 in a month in which he downloaded 50 songs.
B. How much would
he have to pay if he downloaded s songs?
Total amount Parker will pay for s songs = $6 + $0.50 * s
= $6 + $0.50s
Total amount Parker will pay for s songs = 6 + 0.50s
Answer:
y= 3×3×3
y=9+6
y=(15)
semoga membantu
Step-by-step explanation:
i'm sorry ya kalo jawaban nya salah
Answer:
Step-by-step explanation:
For some read I can’t see the pictures