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3 years ago

Help me please ! (: (6th grade)

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

$64.99

Step-by-step explanation:

A total of $584.91 was spent among 9 people (Caleb + 8 friends), thus we can find the amount per person. $584.91 \text{ dollars}/9\text{ people} = 64.99 \text{ dollars}/\text{person}$

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Convert the equation from Standard Form to Slope Intercept Form. Show all of your work using inverse operations. 8x + 4y = 16, s

andreev551 [17]

Basiclaly solve for y
8x+4y=16
minus 8x both sides
4y=-8x+16
divide by 4 both sides
y=-2x+4

6 0

3 years ago

Factor/simply x^2-3x+9/4<br> (Please explain also)

Burka [1]

Answer: PSR (Perfect Square Rule) = (x-3/2)^2

The you simplify.... = x^2 - 3x + 9/4

Step-by-step explanation: Factor by using the PSR (Perfect Square Rule). Then you have to simplify.

Hope this helps you out! ☺

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2 years ago

Using the equation y = 3x – 5, what would the output be for an input of 4

SSSSS [86.1K]

The input is the x-coordinate and the output is the y-coordinate. If the input is 4, plug 4 into the x variable to find the output, y.

y=3(4)-5
y=12-5
y=7

The output is 7.

8 0

2 years ago

Read 2 more answers

A football team lost 9 yards on each of two consecutive plays. represent the total change as a product of sun numbers and then f

dexar [7]

2(-9)=-18
Do the total list is -18 yards

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3 years ago

A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de

olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

And the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

$Se=\frac{\sigma}{\sqrt{n}}$

If we replace the values given we have:

$Se=\frac{12}{\sqrt{100}}=1.2$

So then the distribution for the sample mean $\bar X$ is:

$\bar X \sim N(\mu=80,Se=1.2)$

5 0

2 years ago