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Alex Ar [27]
2 years ago
7

Please help me i dont understand this

Mathematics
2 answers:
Artyom0805 [142]2 years ago
3 0

Answer:

1260

Step-by-step explanation:

sorry if it's wrong

Rudik [331]2 years ago
3 0

1260 is the answer I think.

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Hiii! Plzz help!
maksim [4K]
1/6 of a minute is also 1/6*60 which equals to ten seconds. To find how many words she can type in 120 seconds, we need to divide 120 by 10 and then multiply the rate. 120/10 = 12, and then we multiply 12 by 8. 12*8=96
8 0
2 years ago
Read 2 more answers
Find the sum
lakkis [162]

Answer:

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

Step-by-step explanation:

Let

S = 2b/(b+a)^2 + 2a/(b^2-a^2)   factor denominator

= 2b/(b+a)^2 + 2a/((b+a)(b-a))     factor denominators

= 1/(b+a) ( 2b/(b+a) + 2a/(b-a))    find common denominator

= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a))   expand

= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a))  simplify & factor

= 2/(b+a)(b^2+a^2)/((b+a)(b-a))  simplify & rearrange

= 2(b^2+a^2)/((b+a)^2(b-a))

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

4 0
3 years ago
Rewrite the radical in exponential form
Kamila [148]

\sqrt[4]{10v}    = \sqrt[4]{10}  \times  \sqrt[4]{v}
4 0
3 years ago
Given sample set A= {1,2,3,4,5} how many items are in the complement of set B if set B= all numbers greater than 2? OPTIONS : 3
Ostrovityanka [42]

Answer:

2

Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

6 0
3 years ago
How many times smaller is 2 × 10^-10 than 4 × 10^-5
natta225 [31]

Answer:

200,000

Step-by-step explanation:

To find how many times smaller is smaller number than greater number, divide greater number by smaller number.

Greater number =4\times 10^{-5}

Smaller number =2\times 10^{-10}

Then

\dfrac{\text{Greater number}}{\text{Smaller number}}\\ \\=\dfrac{4\times 10^{-5}}{2\times 10^{-10}}\\ \\=\dfrac{4}{2}\times \dfrac{10^{-5}}{10^{-10}}\\ \\=2\times \dfrac{1}{10^{-5}}\\ \\=2\times 10^5\\ \\=2\times 100,000\\ \\=200,000

7 0
3 years ago
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