Answer:
(B) 0.74 + or - 2.797 × 0.22/√25
Step-by-step explanation:
Confidence Interval = mean + or - t × sd/√n
mean = 0.74 hours
sd = 0.22 hours
n = 25
degree of freedom = n - 1 = 25 - 1 = 24
Confidence level = 99%
t-value corresponding to 24 degrees of freedom and 99% confidence level is 2.797
Confidence Interval = 0.74 + or - 2.797 × 0.22/√25
Probability (Ball goes into hole) = 0.22388 or 22.388%
Step-by-step explanation:
Given:
Ball goes into hole = 15 times
Ball miss the hole = 52 times
Find:
Probability (Ball goes into hole)
Computation:
Total number of tries = 15 + 52
Total number of tries = 67
Probability (Ball goes into hole) = 15 / 67
Probability (Ball goes into hole) = 0.22388 or 22.388%
You should collect the variable on the left side since you can't have two variables of the same letter on each side.so you would take the variable from the right side and subtract it from the left. So subtract x on both sides. Your new problem is 2x-10 is greater than or equal to 0. Now you add 10 on both sides. Your new problem is 2x is greater than or equal to 10. Now divide by 2 on both sides. Your answer would be x is greater than or equal to 5
Step-by-step explanation:
This is what I know there are 54 students who learn salsa and 23 ballet left with 31 students (put that aside) then 15 who learned salsa instead of ballet. (31 - 15 = 16. Left with 16) but 10 who did not learn either ballet or salsa (16-10 = 6.)
Do u understand where I'm going.......Im starting to get confuse myself now
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Answer:
68%
Step-by-step explanation:
<em><u>68-95-99.7% Rule:</u></em>
<em><u /></em>
This is the empirical rule which is used to remember the percentage of values that is within a band of the mean. We say:
- 68% of the data fall within 1 standard deviation of the mean
- 95% of the data fall within 2 standard deviation of the mean, and
- 99.7% of data falls within 3 standard deviations of the mean
Clearly, from the empirical rule, we see that about 68% of the area is between z = -1 and z = 1 (or within 1 standard deviation of the mean)
