No i dont think you can because if you have 7 ones and one 5 that wouldnt be 20 i.d.k tho
Ok, im guessing that this is all about mean
First mean is just adding everything up for example:
5+5+10+10+5
so the answer is 35, but that isnt completely finished you need to divide 35 by 5, or how many numbers were added then you get the mean for my example the mean is 7
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ACTUAL PROBLEMS
1. 10+15+14+8+18+11+12+12+10+10+17+16 = 153
153/12= 12.75
2. 16.4+17.1+17.4+18.1= 69 B)
69/4=17.25
3. 11+15+19+17+23+20+17+13+18+21=174
174/11=15.8181818182
4. 21+25+36+16+32= 130
130/5=26
a
The answer is 8
you would multiply 10,560 by 4,because there's 4 half hours in 2 hours, and then you get 42,240 and divide that number by 5,280 and you end up with 8.
Answer:
The answer is (-4) and (-7).
Step-by-step explanation:
<h3><u>Given</u>;</h3>
<h3>
<u>To </u><u>Find</u>;</h3>
<h3>
<u>Formula</u>;</h3>
Now, for common difference (d)
d = a₂ – a₁ = 2 – 5 = -3
d = a₃ – a₂ = (-1) – 2 = -3
Here, common difference is same everywhere.
So, for fourth term or n = 4
aₙ = a + (n – 1) × d
a₄ = 5 + (4 – 1) × (-3)
a₄ = 5 + 3 × (-3)
a₄ = 5 – 9
a₄ = -4
Then, for fifth term or n = 5
a₅ = 5 + (5 – 1) × (-3)
a₅ = 5 + 4 × (-3)
a₅ = 5 – 12
a₅ = -7
Thus, The fourth term is (-4) and fifth term is (-7).
Answer:
y = x⁴ + x³ - 3x² + 5x + C
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Separable differential equations such as these ones can be solved by treating dy/dx as a ratio of differentials. Then move the dx with all the x terms and move the dy with all the y terms. After that, integrate both sides of the equation.

In general (understood that +C portions are still there),

Note that ∫dy = y since it is ∫1·dy = ∫y⁰ dy = y¹/(0+1) = y
For the right-hand side, we use the sum/difference rule for integrals, which says that
![\int \big[f(x) \pm g(x)\big]\, dx = \int f(x)\,dx \pm \int g(x) \, dx](https://tex.z-dn.net/?f=%5Cint%20%5Cbig%5Bf%28x%29%20%5Cpm%20g%28x%29%5Cbig%5D%5C%2C%20dx%20%3D%20%5Cint%20f%28x%29%5C%2Cdx%20%5Cpm%20%5Cint%20g%28x%29%20%5C%2C%20dx)
Applying these concepts:

The answer is y = x⁴ + x³ - 3x² + 5x + C