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zlopas [31]
3 years ago
8

Solve for x b

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Step-by-step explanation:

10x+1=12x-5

1+5=12x-10x

6=2x

6/2=2x/2

3=x

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Need help ASAP!<br> Can you make $20 by using seven $1 and $5 bills?
Varvara68 [4.7K]
No i dont think you can because if you have 7 ones and one 5 that wouldnt be 20 i.d.k tho
6 0
3 years ago
What is the mean of the data set?
mestny [16]

Ok, im guessing that this is all about mean

First mean is just adding everything up for example:

5+5+10+10+5

so the answer is 35, but that isnt completely finished you need to divide 35 by 5, or how many numbers were added then you get the mean for my example the mean is 7

------------------------------------------------

ACTUAL PROBLEMS

1. 10+15+14+8+18+11+12+12+10+10+17+16 = 153

153/12= 12.75

2. 16.4+17.1+17.4+18.1= 69 B)

69/4=17.25

3.  11+15+19+17+23+20+17+13+18+21=174

174/11=15.8181818182

4. 21+25+36+16+32= 130

130/5=26

a

6 0
3 years ago
Aaron walks at a pace of 10,560 feet per half hour. How many miles does Aaron
yarga [219]
The answer is 8
you would multiply 10,560 by 4,because there's 4 half hours in 2 hours, and then you get 42,240 and divide that number by 5,280 and you end up with 8.
7 0
3 years ago
Find the next two numbers in the sequence 5,2,-1,…
Nataly_w [17]

Answer:

The answer is (-4) and (-7).

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • a₁ = 5
  • a₂ = 2
  • a₃ = (-1)
<h3><u>To </u><u>Find</u>;</h3>
  • a₄ = ?
  • a₅ = ?
<h3><u>Formula</u>;</h3>
  • aₙ = a + (n – 1) × d

Now, for common difference (d)

d = a₂ – a₁ = 2 – 5 = -3

d = a₃ – a₂ = (-1) – 2 = -3

Here, common difference is same everywhere.

So, for fourth term or n = 4

aₙ = a + (n – 1) × d

a₄ = 5 + (4 – 1) × (-3)

a₄ = 5 + 3 × (-3)

a₄ = 5 – 9

a₄ = -4

Then, for fifth term or n = 5

a₅ = 5 + (5 – 1) × (-3)

a₅ = 5 + 4 × (-3)

a₅ = 5 – 12

a₅ = -7

Thus, The fourth term is (-4) and fifth term is (-7).

5 0
2 years ago
Calculate y as a function of x when dy/dx = 4x3 + 3x2 - 6x + 5
PtichkaEL [24]
Answer:
y = x⁴ + x³ - 3x² + 5x + C

======

Separable differential equations such as these ones can be solved by treating dy/dx as a ratio of differentials. Then move the dx with all the x terms and move the dy with all the y terms. After that, integrate both sides of the equation.

   \begin{aligned}&#10;\dfrac{dy}{dx} &= 4x^3 + 3x^2 - 6x + 5 \\&#10;dy &= (4x^3 + 3x^2 - 6x + 5) dx \\&#10;\int dy &= \int (4x^3 + 3x^2 - 6x + 5) dx &#10;\end{aligned}

In general (understood that +C portions are still there), 

   \int x^{m} = \dfrac{x^{m+1}}{m+1}

Note that ∫dy = y  since it is ∫1·dy = ∫y⁰ dy = y¹/(0+1) = y
For the right-hand side, we use the sum/difference rule for integrals, which says that

   \int \big[f(x) \pm g(x)\big]\, dx = \int f(x)\,dx \pm \int g(x) \, dx

Applying these concepts:

   \begin{aligned} &#10; \int dy &= \int (4x^3 + 3x^2 - 6x + 5) \, dx \\&#10;y &= \int 4x^3\,dx + \int 3x^2 \, dx - \int 6x\, dx + \int 5\, dx \\&#10;&= \frac{4x^4}{4} + \frac{3x^3}{3} - \frac{6x^2}{2} + 5x + C \qquad \text{(only one $C$ is needed)} \\&#10;&= x^4 + x^3 - 3x^2 + 5x + C&#10;\end{aligned}

The answer is y = x⁴ + x³ - 3x² + 5x + C
6 0
3 years ago
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