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boyakko [2]
3 years ago
9

Is 17/2 rational or irrational?

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

it's a Rational number

Step-by-step explanation:

because it repeats and stops

Katyanochek1 [597]3 years ago
5 0

Hi, I'm happy to help!

A number is rational if it repeats itself, or stops. This number, both in fraction and decimal form (8.5), stops. This means that the number is rational.

I hope this was helpful, keep learning! :D

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tiny-mole [99]
1/12 + 1/6x = 3/4...multiply everything by common denominator of 12
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x = 8/2
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5 0
3 years ago
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Measure the length of the top of your desk in centimeters.describe how you found the length
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Can someone please help me
Marrrta [24]

Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.

<h3>How to find the value of a trigonometric function</h3>

Herein we must make use of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions to find the right value. According to trigonometry, both cosine and sine are <em>negative</em> in the <em>third</em> quadrant. Thus, by using the <em>fundamental trigonometric</em> expression (sin² α + cos² α = 1) and substituting all known terms we find that:

\sin \theta = -\sqrt{1 - \cos^{2}\theta}

\sin \theta = - \sqrt{1 - \left(-\frac{13}{30} \right)^{2}}

sin θ ≈ - √731 / 30

Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

7 0
2 years ago
Evaluate the function for the given value: f(x)=2x (to the power of 2) -5x-17, find f(-3)
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Answer:

f(-3) = 16

Step-by-step explanation:

You substitute -3 to x.

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f(-3) = 16.

As for the coordinates, the coordinates plotted in the graph above are (1,-1) and (2,-2).

7 0
3 years ago
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Work out the formula of the nth term in the following quadratic sequence:<br> 19, 15, 9, 1...
Butoxors [25]

In a quadratic sequence we'll get a linear first difference and a constant second difference.  Let's verify that.

n          1   2   3   4

f(n)       19  15  9   1

1st diff   -4  -6  -8

2nd diff     2   2

We see that we got a constant second difference.  We could just extend that and work back up to get more values.

n          1   2   3   4       5    6      7

f(n)       19  15  9   1      -9   -21   -35

1st diff   -4  -6  -8   -10  -12   -14

2nd diff     2   2    2     2    2

That's just an aside; we're after the general formula.  We have

f(1)=19, f(2)=15, f(3)=9

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f(n) = an²  + bn + c

We get three equations in three unknowns,

19 = a(1²)+b(1)+c = a+b+c

15 = a(2²) + b(2) + c = 4a + 2b + c

9 = a(3²) + b(3) + c =  9a + 3b + c

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4 = -3a - b

6 = -5a - b

Subtracting those,

-2 = 2a

a = -1

b = -3a -4 = -1

c = 19-a-b = 21

Answer: f(n) = -n² - n + 21

Check:

f(1) = -1 - 1 + 21 = 19, good

f(2) = -4 - 2 + 21 = 15, good

f(3) = -9 - 3 + 21 = 9, good

f(4) = -16 - 4 + 21 = 1, good

Let's check our extended table, how about

f(7)= -49 - 7 + 21 = -35, good

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