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ipn [44]
3 years ago
6

Angle one and two add up to 100, if angle one is 2x and angle two is 3x, what is x?

Mathematics
1 answer:
kifflom [539]3 years ago
5 0

Answer:

angle \: 1 = 2x \\ angle 2 = 3x \\ sum = 1 00 \\ 2x + 3x = 100 \\ 5x = 100 \\ divide \: both \: side \: by \: 5 \\  \frac{5x}{5}  =  \frac{100}{5}  \\ x = 20

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Step-by-step explanation:

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2 years ago
Q # 9 please find the area
Rudik [331]
To solve this problem you must apply the formula for calculate the surface area of a circle, which is shown below:
 SA=πir^2
 where r is the radius of the circle
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6 0
3 years ago
Read 2 more answers
The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had th
Maru [420]

Student 4 has the largest percent error.

Step-by-step explanation:

The percent error of a measurement is given by

p=\frac{|x-x_{true}|}{x_{true}}\cdot 100

where

x is the value of the measurement

x_{true} is the actual value

For student 1:

x=49\\x_{true}=50

Percent error:

p=\frac{|49-50|}{50}\cdot 100=0.02\cdot 100=2\%

For student 2:

x=25.5\\x_{true}=25

Percent error:

p=\frac{|25.5-25|}{25.5}\cdot 100=0.0196\cdot 100 = 1.96\%

For student 3:

x=7.5\\x_{true}=8

Percent error:

p=\frac{|7.5-8|}{8}\cdot 100=0.0625\cdot 100 = 6.25\%

For student 4:

x=2.1\\x_{true}=1.6

Percent error:

p=\frac{|2.1-1.6|}{1.6}\cdot 100=0.3125\cdot 100 = 31.25\%

So, student 4 has the largest percent error.

Learn more about errors:

brainly.com/question/2764830

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4 0
4 years ago
AB is the angle bisector of CAD. Solve for the missing variable?
Alika [10]

Answer:

x=8^\circ

Step-by-step explanation:

A bisector is the line that divides an angle (which in this case is \angle CAD) exactly in half. Therefore, \angle CAB = \angle BAD and as such we can solve for x:

\angle CAB &= \angle BAD\\33^\circ &= 4x + 1^\circ\\4x = 32^\circ\\x = 8^\circ

and we are done.

4 0
3 years ago
the larger of two number is nine more than four times the smaller number. the sum of the two numbers is fifty-nine. find the two
VLD [36.1K]
This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y. 
We are told that X + Y = 59
 We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59    [then combine like terms]
9+5Y=59            [subtract 9 from both sides]
5Y=50                   [divide both sides by 5 to isolate the Y]
Y=10                      [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
4 0
3 years ago
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