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3 years ago

PLS HELP ME I WILL MARK YOU AS BRAINLIEST!!!

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer:

volume = length x width x height

v=11x5x11 = 605

hope that answers your question

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What is the inequality shown?

Lady bird [3.3K]

It shows the interval

[-2,8) or -2≤x<8

7 0

2 years ago

Please help! I will mark the Brainliest!! The engines of a plane are pushing it due north 300 mph and the wind is blowing at a r

valkas [14]

Answer:

the plane is traveling with a speed of 156.44mph

Step-by-step explanation:

Find the attached explanation.

3 0

3 years ago

There are 416 students who are enrolled in an introductory geology course. if there are seven boys to every six girls, how many

Alenkinab [10]

$\text{Let the number of boys be x and number of girls be y.}\\
\\
\text{and there are total 416 students enrolled in the course. so we have}\\
\\
x+y=416 \ \ \ \ \ \ \ \ \ \ ......(i)\\
\\
\text{also given that there are seven boys to every six girls, that is}\\
\\
\frac{x}{y}=\frac{7}{6}$

$\Rightarrow 6x=7y\\
\\
\Rightarrow y=\frac{6x}{7}\\
\\
\text{substitute this value of y in (i), we get}\\
\\
x+\frac{6x}{7}=416\\
\\
\Rightarrow \frac{7x+6x}{7}=416\\
\\
\Rightarrow \frac{13x}{7}=416\\
\\
\Rightarrow x=\frac{416\times 7}{13}\\
\\
\Rightarrow x=224$

Hence the number of boys in the course are: 224

4 0

4 years ago

Is negative 5 a rational number

katen-ka-za [31]

Yes and rational numbers are numbers that can be written as a ratio of two integers

8 0

3 years ago

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$

Hence verified. ✔

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘$

7 0

2 years ago