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3 years ago

PLS HELP ME I WILL MARK YOU AS BRAINLIEST!!!

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer:

volume = length x width x height

v=11x5x11 = 605

hope that answers your question

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Sindrei [870]

A= 15+z+ square root 17(z+15)/ z-2
z=2a^2/(a-1)^2 + 30a/(a-1)^2 - 15/(a-1)^2

6 0

3 years ago

Solve the equation for x. x + 3 /6 = x - 6/ 3 A) 9 B) 12 C) 15 D) 18

Strike441 [17]

Answer:

Step-by-step explanation:

7 0

4 years ago

HELP ASAP PLEASE!!! PLEASE SHOW WORK Calculate how many fluid ounces (fl oz) of water is needed if a recipe requires 2 cups of w

artcher [175]

Answer:

16 fl oz

Step-by-step explanation:

1 cup of H2O is 8 fluid ounces

So, if we have 2 cups, we multiply 8 by 2 to get 16 fl oz.

3 0

3 years ago

How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x

Lena [83]

9514 1404 393

Answer:

the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.

5 0

2 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }$ and a bit more to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }$

Bring up the lower fraction and flip it to divide to get

$tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1}$ which of course simplifies to

-3. Choice A.

6 0

3 years ago