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777dan777 [17]
3 years ago
11

-6+-3-(-18)? what is the answer to this problem?

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

9

Step-by-step explanation:

-6 + -3 - (-18)

-6 - 3 + 18

-9 + 18

9

- (-) = +

+ (+) = +

- (+) = -

+ (-) = -

IgorLugansk [536]3 years ago
5 0

The answer to this problem is 9.

-6+(-3)-(-18)

Since (+)(-)=(-) and (-)(-)=(+),

-6-3+18

-9+18

9

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A stone is launched into the air from a height of 240 feet. The height, h, of the stone, in feet, t seconds after launch is give
rosijanka [135]

A projectile is an object <u>launched</u> into space, and moving under the <em>influence</em> of <u>gravity</u> and <u>momentum</u>. The <em>stone</em> here is an example. Thus, the <em>time</em> taken for the stone to reach the ground is 10 seconds.

On <em>launching</em> of the stone into <u>space</u>, it behaves as a <u>projectile</u>. Thus moving under the <em>influence</em> of gravity and its momentum. Its <u>momentum</u> is the <em>product</em> of its <u>mass </u>and <u>velocity</u>.

The height h, is given as:

h = 16t^{2} + 32t + 240

Differentiating the expression with respect to t, we have;

32t + 32 = 0

t = -1 seconds

Substitute the value of time, t, in the equation for the height;

h = 16 - 32 + 240

  = 224

h = 224 m

Total height, S = 240 + 224

                         = 464

S = 464 m

The total height covered by the stone is 464 m.

From the second equation of <em>free fall</em>,

S = Ut + \frac{1}{2}gt^{2}

S = \frac{1}{2}gt^{2}

464 = \frac{1}{2}*9.8*t^{2}

t^{2} = \frac{928}{9.8}

  = 94.694

t = \sqrt{94.694}

 = 9.7311

t ≅ 10 seconds

The <em>time taken</em> for the stone to hit the ground is 10 seconds.

Thus option A is the required answer.

Visit: brainly.com/question/13834669

7 0
3 years ago
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