 What is the equation of a circle with its center at (-5,2) and a radius of 5? IF YOU DONT KNOW DONT ANSWER PLEASE
1 answer:
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Using the zero product property you can set each expression equal to 0 (or factor for some of them)
All you have to do is set them equal to zero and simplify to solve for x
a. (x+13)=0
x= -13
(x-7)=0
x=7
b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3
c. x=0
(x-3)=0
x=3
d.
needs to be factored
factor out an x to get:
x(x-5) and set each equal to 0
x = 0
(x-5)=0
x=5
e.
also needs to be factored
(x-7)(x+5)=0
(x-7)=0 (x+5)=0
x=7 x=-5
f.
Also needs to be factored using the ac method:
(3x-1)=0
x=1/3
(x+5)=0
x=-5
I hope this helps! (if so, give brainliest please!!)
All you have to do is set them equal to zero and simplify to solve for x
a. (x+13)=0
x= -13
(x-7)=0
x=7
b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3
c. x=0
(x-3)=0
x=3
d.
factor out an x to get:
x(x-5) and set each equal to 0
x = 0
(x-5)=0
x=5
e.
(x-7)(x+5)=0
(x-7)=0 (x+5)=0
x=7 x=-5
f.
Also needs to be factored using the ac method:
(3x-1)=0
x=1/3
(x+5)=0
x=-5
I hope this helps! (if so, give brainliest please!!)