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dezoksy [38]
3 years ago
13

Use this graph to make an equation using y= mx+b (worth 5 points) ​

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

y=5/3x+2

Step-by-step explanation:

antoniya [11.8K]3 years ago
5 0

Answer:

y=5/3x+2

Step-by-step explanation:

go to where the line passes through the line and then find where it does it again that it your slope witch is rise over run to find to the y intercept it is where the line passe the y acais so 2

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People are randomly chosen from a group of 7 boys and 5 girls. Determine which scenario is more likely to happen.
andre [41]

Answer:

A

Step-by-step explanation

Well the boys can be chosen again all in a row but the girls cdan't therfore the answer is A

Hope This Was Helpful!

6 0
2 years ago
In right triangle PQR PR=17 RQ=15 PQ =8 What is tan P<br><br> What is the answer
Delvig [45]

Answer:

The value of tan P  = 1.875

Step-by-step explanation:

Given:

PR=17

RQ=15

PQ =8

To find:

tan P = ?

Solution:

In trigonometric ratio

tan = \frac{opposite}{adjacent}

Now on substituting the given values(refer the figure)

tan (P) =\frac{15}{8}

tan (P) = 1.875

6 0
3 years ago
19.(06.02 LC)
lukranit [14]

Answer:

y = -3x + 7

Step-by-step explanation:

when they are parallel, they always have the same slope.

7 0
3 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
Read 2 more answers
What is the probability that a fair die never comes up an even number when it is rolled six times? (note: enter the value of pro
seropon [69]
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:

Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.

Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64

Therefore, the probability is 1/64 or 1.56%.
6 0
3 years ago
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