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Aliun [14]
3 years ago
6

Suppose the total weight of the fish caught stayed the same but instead of 100 fish caught during the weeklong fishing trip only

10 fish were caught. How would the weight of each fish change?
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0
The weight of each fish would be multiplied by 10.

Assume the first time, the weight was 800 lb.  Since there were 100 fish caught, the weight of each fish would be 800/100 = 8 lb.

This time, however, only 10 fish were caught.  The weight would be 800/10 = 80 lb.  

80 = 8(10), so the weight is 10 times more.
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ron walks 0.5 mile on track on the track in 10 minutes. stevie walks 0.25 mile on the track in 6 minutes. find the unit rate for
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8 0
3 years ago
Explain the reasoning please
Svet_ta [14]

Step-by-step explanation:

Something to keep in mind is that anything greater than 0 is positive and anything less than 0 is negative

a is to the right of 0 and 1 making it a positive number

b is to the left of 0 making is a negative number

A. a is greater than 1 and b is a negative number

negative number * positive number = negative number

We already know that a is greater than 1 so ab has to be much less than -1 making ab+1 a negative expression

B. Looking at the number line, you can tell that the distance between 1 and a is a bit less than the distance between 0 and 1

This means that a= 1.x not 2

Because of this, a-2 is negative

C. -b

b is a negative number which means that -b would be positive

D. a+b

Looking at the number line, you can tell that the distance between 0 and a is less than the distance between 0 and b

Therefore, a+b is negative

E. a-b

Since b is already negative, the expression would simplify to two positive numbers being added

This means that a-b can't be negative

F. a-1

The number line shows us that a is greater than 1, therefore, a minus 1 would be positive

I hope this helps in some way or another

7 0
3 years ago
Read 2 more answers
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