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Aliun [14]
3 years ago
6

Suppose the total weight of the fish caught stayed the same but instead of 100 fish caught during the weeklong fishing trip only

10 fish were caught. How would the weight of each fish change?
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0
The weight of each fish would be multiplied by 10.

Assume the first time, the weight was 800 lb.  Since there were 100 fish caught, the weight of each fish would be 800/100 = 8 lb.

This time, however, only 10 fish were caught.  The weight would be 800/10 = 80 lb.  

80 = 8(10), so the weight is 10 times more.
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What is the area of this figure?
insens350 [35]

Answer:

54 units squared

Step-by-step explanation:

You have to divide the shape into simpler shapes such as rectangles and triangles that you can easily find the area of. Then, add those areas together. I divided it into one rectangle and three triangles.

Rectangle 1: length=7 width=6          6(7)=42

Triangle 1: base=6 height=2          1/2(6)2=6

Triangle 2: base=3 height=2          1/2(3)2=3

Triangle 3: base=6 height=1          1/2(6)1=3

Area= R1+T1+T2+T3= 42+6+3+3= 54 units squared

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3 years ago
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HACTEHA [7]
You'll have to do the actual multiplication here:

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 -------------------- = -----  *  ---------------------------
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or (1/2) (4n^2 + 9n + 2), which, after mult., becomes

(1/2)(4n^2) + (1/2)(9n) + 1


This simplifies to 2n^2 + (9/2)n + 1

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3 years ago
You share a coin collection with a friend. You possess 44 of the coins and
vfiekz [6]

Answer:

Step-by-step explanation:

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HELP!! I desperately need help!! I would appreciate if you could show work please!!!
zzz [600]

Answer:

a) 137.9°

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Step-by-step explanation:

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1b) A complementary angle will equal 90°, so you need to use the expression given and add an x for the other part of 90°

8x-20+x = 90

9x-20=90

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