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Aliun [14]
4 years ago
6

Suppose the total weight of the fish caught stayed the same but instead of 100 fish caught during the weeklong fishing trip only

10 fish were caught. How would the weight of each fish change?
Mathematics
1 answer:
Paha777 [63]4 years ago
4 0
The weight of each fish would be multiplied by 10.

Assume the first time, the weight was 800 lb.  Since there were 100 fish caught, the weight of each fish would be 800/100 = 8 lb.

This time, however, only 10 fish were caught.  The weight would be 800/10 = 80 lb.  

80 = 8(10), so the weight is 10 times more.
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Answer:

1/6

Step-by-step explanation:

if there are 6 sides on a dice and the space is 3 moves away, then you have a 1/6 chance of rolling a 3 and landing on it.

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17 The table shows some information about the dress sizes of 25 women.
eimsori [14]

Answer:

8.5 or 8½

Step-by-step explanation:

Arranged numbers in ascending order

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Therefore median = 8 + 9 divided by 2

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3 years ago
Solve 4y - 7 =29<br><br> Quickly done
Murljashka [212]

Answer:

y=9

Step-by-step explanation:

4y-7=29

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3 years ago
Give at least five problems solving about area of a sector of a circle.
Katyanochek1 [597]

See below for the examples of sectors and arcs of a circle

<h3>Area of sector of a circle</h3>

The area of a sector is calculated as:

A = \frac{\theta}{360} * \pi r^2 ---- when the angle is in degrees

A = \frac{\theta}{2} *r^2 ---- when the angle is in radians

Take for instance, we have the following problems involving sector areas

Calculate the area of a sector where the radius of the circle is 7, and

  1. The central angle is 30 degrees
  2. The central angle is π/12 rad
  3. The central angle is 90 degrees
  4. The central angle is π/4 rad
  5. The central angle is 180 degrees

Using the above formulas, the sector areas are:

1. A = \frac{30}{360}* \frac{22}{7} * 7^2 = 12.83

2.  A = \frac{\pi}{12} * 7^2 = 12.83

3. A = \frac{90}{360}* \frac{22}{7} * 7^2 = 38.5

4. A = \frac{\pi}{2} * 7^2 = 38.5

5. A = \frac{180}{360}* \frac{22}{7} * 7^2 = 77

<h3>Examples of arc length</h3>

The length of an arc is calculated as:

L= \frac{\theta}{360} * 2\pi r ---- when the angle is in degrees

L = r\theta ---- when the angle is in radians

Take for instance, we have the following problems involving arc lengths

Calculate the length of an arc where the radius of the circle is 7, and

  1. The central angle is 30 degrees
  2. The central angle is π/12 rad
  3. The central angle is 90 degrees
  4. The central angle is π/4 rad
  5. The central angle is 180 degrees

Using the above formulas, the arc lengths are:

1. L = \frac{30}{360}* 2 * \frac{22}{7} * 7 = 3.7

2.  L = \frac{\pi}{12} * 7 = 3.7

3. L = \frac{90}{360}*2 * \frac{22}{7} * 7 = 11.0

4. L = \frac{\pi}{4} * 7 = 11

5. L = \frac{180}{360}*2 * \frac{22}{7} * 7 = 22

<h3>Examples of the arcs of a circle</h3>

The examples include:

  • A parabolic path
  • Distance in a curve
  • Curved bridges
  • Pizza
  • Bows

Read more about arc and sectors at:

brainly.com/question/15955580

#SPJ1

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Olenka [21]

Answer:

14.5 feet

Step-by-step explanation:

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