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sp2606 [1]
3 years ago
9

Mr. Hayes has 111 straw bundles to use for bedding in his horse stalls.What is the greatest number of stalls he can fill if each

stall holds exactly 4 bundles of straw?
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
111 straw bundles / 4 per stall = 27.75
However, you can’t technically have a .75 of a stall, so you round down to the nearest whole number, which is 27.
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Total blood cholesterol level was measured for each of
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<h3>Answer: Mean = 218.9.</h3><h3>Median = 229</h3><h3>Mode = Zero mode.</h3>

Step-by-step explanation:

Given blood cholesterol level was measured for each of 8 adults (in mg/dL) are:

264, 191, 160, 148, 262, 212, 268, 246

In order to find the mean, we need to add all those 8 numbers and divide by 8.

Therefore, mean = \frac{264+191+160+148+262+212+268+246}{8} =\frac{1751}{8} =218.9.

<h3>Mean = 218.9.</h3>

In order to find the median, we need to arrange them in ascending order:

148, 160, 191, 212, 246, 262, 264, 268.

The middle most two values are 212 and  246.

Therefore, median = \frac{212+246}{2} =\frac{458}{2} = 229.

<h3>Median = 229.</h3>

\mathrm{The\:mode\:is\:the\:term\:in\:the\:data\:set\:that\:appears\:the\:most.}

\mathrm{If\:there\:is\:more\:than\:one\:term\:that\:appears\:the\:most,\:then\:there\:is\:no\:mode.}

\mathrm{Count\:the\:number\:of\:times\:each\:element\:appears\:in\:the\:list}

\begin{pmatrix}148&160&191&212&246&262&264&268\\ 1&1&1&1&1&1&1&1\end{pmatrix}

\mathrm{The\:most\:common\:element\:is\:not\:unique,\:so\:there\:is\:no\:mode}

<h3>Therefore, Mode = Zero mode.</h3>
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Step-by-step explanation:

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Answer:62-n

Step-by-step explanation:

Let the first number be n and the second number be w , then :

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w = 62 - n

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