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2 years ago

Combining like terms: 6(7-3y)+6(y+1)I NEED HELP ILL GIVE U ALL MY POINTS!!

Mathematics

2 answers:

Ivanshal [37]2 years ago

8 0

Answer:

48 - 12y

Step-by-step explanation:

6(7-3y)+6(y+1)

Distribute 6.

(42 - 18y) + (6y + 6)

Now add the "y"

42 - 12y + 6

Now add the intergers

48 - 12y

lina2011 [118]2 years ago

6 0

Answer:

-12y + 48 !

Step-by-step explanation:

hope this helps :))

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HURRY ILL GIVE U BRAINLIEST!!! Find the area of each figure. Which do these belong in?

nordsb [41]

Answer:

Area of rectangle PQRS is 14 square units.

Area of triangles UVW and EFG and square ABCD are 16 square units each.

Step-by-step explanation:

Let us find the area of each of the figures shown in the graph.

Area of rectangle PQRS is given as the product of PQ and QS.

From the graph,

Length of PQ = 7 units

Length of QS = 2 units

Now, area of rectangle PQRS = $PQ\times QS=7\times 2=14$ square units.

Now, area of square ABCD is given as the square of any of its side.

From the graph, AB = 4 units.

So, area of ABCD = $AB^{2}=4^2=16$ square units.

Area of triangle UVW is given as the half of the product of its base VW and height UW.

From the graph, UW = 4 units, VW = 8 units

Therefore, area of triangle UVW = $\frac{1}{2}\times UW\times VW=\frac{1}{2}\times 4\times 8=16$ square units.

For triangle EFG, EF = 4 units and FG = 8 units.

Area = $\frac{1}{2}\times EF\times FG=\frac{1}{2}\times 4\times 8=16$ square units.

Area of rectangle PQRS is 14 square units. The remaining figures have areas each equal to 16 square units.

4 0

3 years ago

Sam drove 696 in 12 hours. At this same rate, how long would it take him to drive 464 miles?

MArishka [77]

696/12 = 464/x

696x = 464 *12 ...cross multiply
696x = 5568
x = 5568/696
x=8

answer: 464 miles in 8 hours

8 0

3 years ago

Read 2 more answers

If 3w - 5 = -27, what is the value of w? A -32/3 B 3/32 C 22/-3 D 3/22

tiny-mole [99]

C 22/-3
You use the the equation to plug it in and c is the only fraction that plugs in and equals -27.

3 0

3 years ago

Estimate the sum or difference.

dangina [55]

1) $\frac{4}{6}+\frac{1}{8}=\frac{19}{24}$

2) $\frac{2}{6}+\frac{7}{8}=\frac{29}{24}$

3) $\frac{5}{6}-\frac{3}{8}=\frac{11}{24}$

4) $\frac{4}{6}+\frac{3}{8}=\frac{25}{24}$

5) $\frac{7}{8}-\frac{5}{6}=\frac{1}{24}$

6) $\frac{1}{6}+\frac{7}{8}=\frac{25}{24}$

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

$\frac{4}{6}+\frac{1}{8}=$

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

$4\cdot 4 = 16\\1\cdot 3 = 3$

The expression then becomes:

$\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}$

$\frac{2}{6}+\frac{7}{8}=$

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.

So the new numerators of the two fractions are:

$2\cdot 4 = 8\\7\cdot 3 = 21$

And we get:

$\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}$

$\frac{5}{6}-\frac{3}{8}$

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

$5\cdot 4 = 20\\3\cdot 3 = 9$

And so:

$\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}$

$\frac{4}{6}+\frac{3}{8}=$

Using the same lowest common denominator, 24, the new numerators are:

$4\cdot 4 = 16\\3\cdot 3 = 9$

And so we can rewrite the expression as

$\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}$

$\frac{7}{8}-\frac{5}{6}=$

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

$7\cdot 3 = 21\\5\cdot 4 = 20$