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2 years ago

Combining like terms: 6(7-3y)+6(y+1)I NEED HELP ILL GIVE U ALL MY POINTS!!

Mathematics

2 answers:

Ivanshal [37]2 years ago

8 0

Answer:

48 - 12y

Step-by-step explanation:

6(7-3y)+6(y+1)

Distribute 6.

(42 - 18y) + (6y + 6)

Now add the "y"

42 - 12y + 6

Now add the intergers

48 - 12y

lina2011 [118]2 years ago

6 0

Answer:

-12y + 48 !

Step-by-step explanation:

hope this helps :))

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Forensic scientists use the following law to determine the time of death of accident or murder victims. If T denotes the tempera

Naddik [55]

Answer: He was killed 24.83 hours before the body was found.

Step-by-step explanation:

Since we have given that

$T=T_0+(T_1-T_0)(0.97)^t$

Here, T is the temperature of a body t hr after death, T = 82°F

T₀ is the air temperature , T₀ = 67°F

T₁ is the body temperature at the time of death = T₁ = 98.6°F

So, we will substitute all the values in the above equation.

$82=67+(98.6-67)(0.97)^t\\\\82-67=31.6(0.97)^t\\\\\dfrac{15}{31.6}=(0.97)^t\\\\0.474683544=(0.97)^t\\\\\text{Taking ln on both sides}\\\\\ln(0.474683544)=t\ln(0.97)\\\\-0.745=t\times -0.030\\\\t=\dfrac{0.745}{0.030}\\\\t=24.83\ hours$

Hence, he was killed 24.83 hours before the body was found.

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3 years ago

given abc with a(-4 -2), b(4,4), and c(18,-8). write the equation of the line that contains the altitude that passes through b i

Tresset [83]

check the picture below.

so red line of BD is perpendicular to AC, hmmmm let's firstly find the slope of AC, bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

$\bf A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{18}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-(-2)}{18-(-4)}\implies \cfrac{-8+2}{18+4} \\\\\\ \cfrac{-6}{22}\implies -\cfrac{3}{11} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{11}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{11}{3}}\qquad \stackrel{negative~reciprocal}{\cfrac{11}{3}}}\impliedby \textit{BD's slope}$

so we're really looking for the equation of a line whose slope is 11/3 and runs through B(4,4). Keeping in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf B(\stackrel{x_1}{4}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies \cfrac{11}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=\cfrac{11}{3}(x-4)$

$\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}\textit{ to do away with the denominators}}{3(y-4)=3\left( \cfrac{11}{3}(x-4) \right)\implies 3y-12=11(x-4)} \\\\\\ 3y-12=11x-44\implies 3y=11x-32 \\\\\\ -11x+3y=-32\implies \blacktriangleright 11x - 3y= 32\blacktriangleleft$

4 0

2 years ago

Combining like terms: 6(7-3y)+6(y+1)I NEED HELP ILL GIVE U ALL MY POINTS!!​

Combining like terms: 6(7-3y)+6(y+1)I NEED HELP ILL GIVE U ALL MY POINTS!!