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3 years ago

The ratio of 62 miles to 100 kilometers

Mathematics

1 answer:

Masja [62]3 years ago

4 0

9514 1404 393

Answer:

0.99779328

Step-by-step explanation:

The exact conversion factor is ...

1 mi = 1.609344

Then 62 miles is 62×1.609344 km = 99.779328 km.

The ratio of this to 100 km is ...

99.779328/100 = 0.99779328 . . . . ratio of 62 miles to 100 km

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Use any method to add or subtract (1 point) <br> 5/7 - (3/14 + 3/14)

Ray Of Light [21]

Answer:

5/7 - (3/14 + 3/14) = 2/7

See the steps of solution:

5/7 - (3/14 + 3/14) = Solve parenthesis first
5/7 - (3 + 3)/14 = Add fractions with same denominator
5/7 - 6/14 = Simplify
5/7 - 3/7 = Subtract fractions with same denominator
(5 - 3)/7 = Simplify
2/7 Answer

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1 year ago

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

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3 years ago

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myrzilka [38]

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3 years ago

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A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Ratling [72]

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$ .

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3 years ago

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LenaWriter [7]

Answer:

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Step-by-step explanation:

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3 years ago