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3 years ago

Answer this question.

Mathematics

2 answers:

erastovalidia [21]3 years ago

8 0

Answer:

B. y = -2x + 5

Step-by-step explanation:

By looking at the table of values, as x increases by 1, y decreases by 2. This means the slope is -2. By process of elimination, this leaves with answer B.

Sindrei [870]3 years ago

6 0

The answer is B
Math
Explain

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Factor completely x2 + 20x − 36.

vodomira [7]

Answer:

Prime

Step-by-step explanation:

x² + 20x − 36

You must find a pair of numbers that multiply to give -36 and add to give +20.

The likely candidates are 2 and 18, and they must have opposite signs to give a negative product.

+2 × (-18) = -36; +2 + (-18) = -16

-2 × 18 = -36; -2 + 8 = +16

Neither combination gives +20 as the sum.

The expression can't be factored with rational numbers.

The expression is prime.

5 0

3 years ago

Find the area, in square meters, of an equilateral triangle with a perimeter of 36 m.

Citrus2011 [14]

I hope it helps you!!!

6 0

3 years ago

Need help on this one please answer asap

Oliga [24]

First find the hourly rate by dividing $187 by 11 hours. That yields $11 per hour. Now multiple the $11/hour rate by 8 hours of work resulting in $88.

8 0

3 years ago

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

4 years ago

Which of the following points lies on the circle whose center is at the origin and whose radius is 10?

aliina [53]

The answer is (6,-8)

7 0

3 years ago